Dave drove a total 2250 miles over a period of 15 days. Each day after

Question

Dave drove a total 2250 miles over a period of 15 days. Each day after the first he increased the number of miles he drove in a single day by one mile. What is the difference between the average (arithmetic mean) number of miles he drove per day and the median number of miles driven over the course of the 15 days?

A. 0
B. 1
C. 5
D. 15
E. 25

A. 0
B. 1
C. 5
D. 15
E. 25

gracie · Answer

let x=day 1 miles
15x+  =2250
x=143
median=day 8 miles=143+7=150
mean=2250/15=150
0
A

mohshu · Answer

Bunuel  any solution using Arithmetic progression formula

Sash143 · Answer

The catch here in this question is highlighted.

If he drove "n" miles for the first day, he would drive n+1 miles in the second and so on. It is consecutively increasing. 
And for consecutive integers MEAN = MEDIAN. Hence the difference is 0.
Option A

MathRevolution · Answer

Each day after the first he increased the number of miles he drove in a single day by one mile: This tells us that the miles are increased consecutively.

For consecutive, Median = mean and hence difference is 0.

Answer A

ScottTargetTestPrep · Answer

Solution:

If each day after the first he increased the number of miles Dave drove in a single day by one mile, then the number of miles he drove over the period of 15 days are consecutive numbers. Therefore, the average number of miles he drove per day is equal to the median number of miles driven over the course of the 15 days, and hence the difference is 0.

Answer: A

Dave drove a total 2250 miles over a period of 15 days. Each day after

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Dave drove a total 2250 miles over a period of 15 days. Each day after

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