Answer C
Diana is traveling from Morristown to Lotusville in a car that averages 19 to 25 miles per gallon of gasoline. If her tank is currently 89% full and she fully refuels the tank each time it reaches a quarter tank, what is the greatest amount of gasoline she could have in her tank at the end of her trip?
(1) Tank holds 12 gallons of gas.
(2) The distance between Morristown and Lotusville is 543 miles.
Statement 1)
Tank holds 12 gallons of gas
We don’t know the total distance he has to travel..
Statement 2 )
Total distance is 543 miles
We don’t know the total capacity X of the tank …
Currently 89% full ..=??
1+2
Tank holds 12 gallons of gas and at the beginning is 89% full mean it currently contains 89*12/100 = 10.68 gallons
Total distance to cover is 543 miles
With one gallon, he can cover either 19 or 25 miles
And at 25% of 12galons he refuels the tank
Mean when the tank reach 12/4=3 gallons, he refuels to 12 gallons.
Initial capacity 10.68 -7.68=3 (3 because it’s the least possible value the tank must have)
With 7.68 he will cover 7.68*19 =148.2 or 7.68*25=195
Then after the first 148.2 or 195 miles he will refueled the tank to 12 gallons
He will use 12-3 =9 gallons before the next refueling
With these 9 gallons, he will cover 9*19 or 9*25
The total distance cover in before the 2nd refueling is 9*19+ 148.2=319 or 9*25+195=420
Then he refueled the tank for the second time to 12 gallons
Same process
319+9*19=490miles (total distance not covered)
Fuel the tank again
490+9*19=661>> 543
490+19*B=543 —-> B= 2,78
420+25*9= 645>543 then we have to find how many gallons he used
420+25*A=543 —>A=4,92 gallons used
As we fueled in the 2 times to 12 gallons at an average of 25 miles/gallons and 3 times at 19 miles per gallon
At the end of the trip he could have
12-4,92= 7,08 galon
12-2,78=9,21 galon
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