It is currently 21 Mar 2018, 07:56

# Happening Now:

UVA Darden R2 Results - Join CHAT ROOM for Live Updates  | HBS R2 Results at Noon ET

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Difficult Geometry Quesiton

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Affiliations: CFA L3 Candidate, Grad w/ Highest Honors
Joined: 03 Nov 2007
Posts: 131
Location: USA
Schools: Chicago Booth R2 (WL), Wharton R2 w/ int, Kellogg R2 w/ int
WE 1: Global Operations (Futures & Portfolio Financing) - Hedge Fund (\$10bn+ Multi-Strat)
WE 2: Investment Analyst (Credit strategies) - Fund of Hedge Fund (\$10bn+ Multi-Strat)
Difficult Geometry Quesiton [#permalink]

### Show Tags

04 Aug 2009, 20:23
1
This post was
BOOKMARKED
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Attachments

Quant#12.doc [72 KiB]
Downloaded 457 times

 To download please login or register as a user

Manager
Joined: 29 Jul 2009
Posts: 112
Re: Difficult Geometry Quesiton [#permalink]

### Show Tags

05 Aug 2009, 03:02
for small triangle
Area = 1/2 (s*h) .........h is the height

for bigger triangle
Area = 1/2 (S*H) .........H is the height

From the question we have
1/2 (S*H) = 2 * [1/2 (s*h)]

so S/s = h/H....equation A

For similar triangles

h/H = s/S

so h = (H*s)/S ....equation B

From A and B we get

S= s *sqrt( 2 )

HTH
Manager
Joined: 14 Jun 2009
Posts: 90
Re: Difficult Geometry Quesiton [#permalink]

### Show Tags

05 Aug 2009, 04:50
in your calculation where does the extra '2' go??

From the question we have
1/2 (S*H) = 2 * [1/2 (s*h)]

so S/s = h/H....equation A

it shud be>> S/s= 2 h/H
Intern
Joined: 01 Aug 2009
Posts: 29
Location: Australia
Re: Difficult Geometry Quesiton [#permalink]

### Show Tags

05 Aug 2009, 04:54
apoorvasrivastva wrote:
From the question we have
1/2 (S*H) = 2 * [1/2 (s*h)]

so S/s = h/H....equation A

Hey apoorvasrivastva, the answer is good, I think you made a typo in eq A...
S/s = 2 h/H

Anyway, we can also do this by applying a property of similar triangles, which is:
For similar triangles, the ratio of the corresponding areas is equal to the ratio of the squares of any of the corresponding lengths.

therefore, Triangle Area(right)/Triangle Area(left) = 2/1 = S^2/s^2 => S = s sqrt(2)
_________________

The three most significant times in your life are:
1. When you fall in love
2. The birth of your first child
3. When you prepare for your GMAT

Manager
Joined: 29 Jul 2009
Posts: 112
Re: Difficult Geometry Quesiton [#permalink]

### Show Tags

05 Aug 2009, 07:45
scarish wrote:
apoorvasrivastva wrote:
From the question we have
1/2 (S*H) = 2 * [1/2 (s*h)]

so S/s = h/H....equation A

Hey apoorvasrivastva, the answer is good, I think you made a typo in eq A...
S/s = 2 h/H

Anyway, we can also do this by applying a property of similar triangles, which is:
For similar triangles, the ratio of the corresponding areas is equal to the ratio of the squares of any of the corresponding lengths.

therefore, Triangle Area(right)/Triangle Area(left) = 2/1 = S^2/s^2 => S = s sqrt(2)

hey u r right..i made a typo..sorry folks!!
Senior Manager
Joined: 17 Jul 2009
Posts: 277
Concentration: Nonprofit, Strategy
GPA: 3.42
WE: Engineering (Computer Hardware)
Re: Difficult Geometry Quesiton [#permalink]

### Show Tags

05 Aug 2009, 13:05
if two circles/spheres or whatever of the same shape...

D and d is the length of respective sides
S and s is the (surface) area
V and v is the volume of a 3d shape...

then usually S/s = (D/d)^2, V/v = (D/d)^3...i think this is usually the case. so here would be 2/1 = (D/d)^2, D/d = sqrt(2)
Re: Difficult Geometry Quesiton   [#permalink] 05 Aug 2009, 13:05
Display posts from previous: Sort by

# Difficult Geometry Quesiton

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.