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DIMES , QUARTERS

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Manager
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DIMES , QUARTERS [#permalink]

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New post 27 Jun 2009, 21:29
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One person have quarters coins twice as many as dime coins, he also have half many five cents coins as dime coins, the total money of quarters /total money of five cents?

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Re: DIMES , QUARTERS [#permalink]

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New post 27 Jun 2009, 22:22
vcbabu wrote:
One person has quarters twice as many as dimes. He also has half as many nickels as dime coins. The total of quarters / total nickel?


no of quarters = q
no of dimes = d
no of nickel = n

Total of quarters = 25q
Total of nickel = 5n

n= n
d = 2n
q = 2d = 2x2n = 4n

The total of quarters / total nickel = 25q / 5n = 25 (4n) / 5(n) = 20:1
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Re: DIMES , QUARTERS [#permalink]

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New post 29 Jun 2009, 14:35
vcbabu wrote:
One person have quarters coins twice as many as dime coins, he also have half many five cents coins as dime coins, the total money of quarters /total money of five cents?


So, Q, D, & N represent the number of each type of coin.
We're given Q=2D, D=2N, so we know Q=4N.

Now we can plug in numbers for quarters & nickels. To simplify the plug in, we can say we only have 1 nickel & 4 quarters. So 4Q is 100 cents, & 1N is 5 cents. 100/5=20. The ratio Q amount to N amount will always be 20:1.

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Re: DIMES , QUARTERS   [#permalink] 29 Jun 2009, 14:35
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