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distance

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Manager
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Joined: 14 Jun 2007
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Location: Vienna, Austria
distance [#permalink]

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New post 04 Nov 2008, 01:02
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

guys

can some one tell me - why at the end of the calculation you have to dedcut the distance of the hiker from the distance of the cyclist?
cheers
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Re: distance [#permalink]

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New post 04 Nov 2008, 01:37
The question says that the cyclist waits for the higher 5 minutes after passing the hiker. In these 5 minutes, hiker would travel a certain distance and this distance needs to be reduced from the distance travelled by cyclist in 5 minutes.

I hope, I am clear.

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Re: distance [#permalink]

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New post 04 Nov 2008, 20:02
domleon wrote:
guys

can some one tell me - why at the end of the calculation you have to dedcut the distance of the hiker from the distance of the cyclist?
cheers


We can rephrase the question as: The cycler/hiker are at the same point, they both travel for 5 more minutes, and then the cyclist stops to wait for the hiker.

So in the next 5 minutes (=1/12 of an hour), what happens?
1. The cyclist travels 1/12*20miles = 20/12 miles
2. The hiker travels 1/12*4miles=4/12 miles

Therefore the distance between them is (subtracting) = 16/12 miles = 4/3 of a mile. Have to subtract this since they have both moved within the 5 minute period.

Lastly, the time to catch up is then 4/3 divided by the speed of the hiker = 4/3 * 1/4 = 1/3 of an hour = 20 mins.

--
Having said that - I found the wording confusing to this question, I initially thought it meant that the cyclist only stops for 5 minutes :?

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Re: distance   [#permalink] 04 Nov 2008, 20:02
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