Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 0808:00 AM PDT
-08:30 AM PDT
Join the special YouTube live-stream for selecting the winners of GMAT Club MBA Scholarships sponsored by Juno live. Watch who gets these coveted MBA scholarships offered by GMAT Club and Juno.
28 Aug 2024, 01:30
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
72% (01:26) correct
28%
(01:45)
wrong
based on 88
sessions
History
Date
Time
Result
Not Attempted Yet
Does a Type X machine screw weigh between \(\frac{1}{2}\) and \(\frac{3}{4}\) grams?
(1) A shipment of 2000 Type X machine screws weighs more than 1,000 grams.
(2) A shipment of 400 Type X machine screws weighs less than 260 grams.
(1) A shipment of 2000 Type X machine screws weighs more than 1,000 grams.
(2) A shipment of 400 Type X machine screws weighs less than 260 grams.
28 Aug 2024, 02:07
Kudos
Bookmarks
Changing the range from \(\frac{1}{2}<x<\frac{3}{4}\) to \(\frac{50}{100}<x<\frac{75}{100}\)
(1) A shipment of 2000 Type X machine screws weighs more than 1,000 grams.
Let the weight of a screw = \(x\)
\(\frac{1000}{2000} = \frac{1}{2}\) or \(\frac{50}{100}\)
\(x > \frac{50}{100}\)
This means that the weight of a screw could be between \(\frac{1}{2}\) and \(\frac{3}{4}\), or it could exceed the range.
INSUFFICIENT
(2) A shipment of 400 Type X machine screws weighs less than 260 grams.
Let the weight of a screw = \(x\)
\(\frac{260}{400} = \frac{13}{20}\) or \(\frac{65}{100}\)
\(x < \frac{65}{100}\)
Once again, the weight of a screw could be in the range from the question stem or it could be below it.
INSUFFICIENT
(1+2)
Together one gets the following range for the weight of a screw:
\(\frac{50}{100} < x < \frac{65}{100}\) which means that \(x\) will be in the range of \(\frac{1}{2}<x<\frac{3}{4}\)
SUFFICIENT
ANSWER C
(1) A shipment of 2000 Type X machine screws weighs more than 1,000 grams.
Let the weight of a screw = \(x\)
\(\frac{1000}{2000} = \frac{1}{2}\) or \(\frac{50}{100}\)
\(x > \frac{50}{100}\)
This means that the weight of a screw could be between \(\frac{1}{2}\) and \(\frac{3}{4}\), or it could exceed the range.
INSUFFICIENT
(2) A shipment of 400 Type X machine screws weighs less than 260 grams.
Let the weight of a screw = \(x\)
\(\frac{260}{400} = \frac{13}{20}\) or \(\frac{65}{100}\)
\(x < \frac{65}{100}\)
Once again, the weight of a screw could be in the range from the question stem or it could be below it.
INSUFFICIENT
(1+2)
Together one gets the following range for the weight of a screw:
\(\frac{50}{100} < x < \frac{65}{100}\) which means that \(x\) will be in the range of \(\frac{1}{2}<x<\frac{3}{4}\)
SUFFICIENT
ANSWER C
Moderators:
