Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1308:30 AM PDT
-09:30 AM PDT
In Episode 4 of our GMAT Ninja CR series, we tackle the most intimidating CR question type: Boldface & "Legalese" questions. If you've ever stared at an answer choice that reads, "The first is a consideration introduced to counter a position that...
May 1212:00 PM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.- May 14
08:30 AM PDT
-09:30 AM PDT
Most GMAT test-takers are intimidated by the hardest GMAT Verbal questions. In this session, Target Test Prep GMAT instructor Erika Tyler-John, a 100th percentile GMAT scorer, will show you how top scorers break down challenging Verbal questions.. - Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
06 Nov 2008, 10:10
Kudos
Bookmarks
does anyone have any good material on geometry esp on surface area of 3d objects, volumes, inscribed objects etc.. maybe we can make this a sticky??
I will get started here with some useful formulas to remember
Surface Area
Surface area of a cube=6*a^2 (where a is the side)
surface area of a rectangular box=2ab+2bC+2ac
Surface area of sphere=4*pi*r^2
Surface area of cylinder= 2pi*r^2 + 2pi*r*h
Volume
Cube=a^3
rectangle=a*b*c
cylinder=pi*r^2*h
cone=1/3*pi*r^2*h
pyramid=1/3*B*H
sphere=4/3*pi*r^3
OK, I do remember seeing a question on my exam asking for the comparison of surface area of cone to a cylinder...I have no memory what the surface area of cone is?
I will get started here with some useful formulas to remember
Surface Area
Surface area of a cube=6*a^2 (where a is the side)
surface area of a rectangular box=2ab+2bC+2ac
Surface area of sphere=4*pi*r^2
Surface area of cylinder= 2pi*r^2 + 2pi*r*h
Volume
Cube=a^3
rectangle=a*b*c
cylinder=pi*r^2*h
cone=1/3*pi*r^2*h
pyramid=1/3*B*H
sphere=4/3*pi*r^3
OK, I do remember seeing a question on my exam asking for the comparison of surface area of cone to a cylinder...I have no memory what the surface area of cone is?
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
07 Nov 2008, 01:29
Kudos
Bookmarks
you made me think re: the surface area of a cone...
it is area of the circular base = pi r^2 + pi x r x (length of the side)
also found the below link with math formulae for some common shapes. HTH
https://math.about.com/library/blmeasurement.htm
it is area of the circular base = pi r^2 + pi x r x (length of the side)
also found the below link with math formulae for some common shapes. HTH
https://math.about.com/library/blmeasurement.htm
07 Nov 2008, 02:02
Kudos
Bookmarks
I look at the surface area of a cone as below.
If r is the radius of the base and h is the height of the cone then \(sqrt{r^2 + h^2}\) will be the slanted height of the cone. Now, the side area of cone is actually the area of a circle with the radius as the slanted height of the cone. Hence, we can find this area and add to the area of the base.
If r is the radius of the base and h is the height of the cone then \(sqrt{r^2 + h^2}\) will be the slanted height of the cone. Now, the side area of cone is actually the area of a circle with the radius as the slanted height of the cone. Hence, we can find this area and add to the area of the base.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
