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# Does curve (x-a)^2 + (y-b)^2 = 16 intersect the Y axis? 1.

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CEO
Joined: 21 Jan 2007
Posts: 2598
Location: New York City
Does curve (x-a)^2 + (y-b)^2 = 16 intersect the Y axis? 1.  [#permalink]

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28 Nov 2007, 12:48
1
Does curve (x-a)^2 + (y-b)^2 = 16 intersect the Y axis?

1. a^2 + b^2 > 16
2. a = |b| + 5

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CEO
Joined: 17 Nov 2007
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Concentration: Entrepreneurship, Other
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28 Nov 2007, 13:05
B.

(x-a)^2 + (y-b)^2 = 16 means circle in center (a,b) and radius of 4.

1. a^2 + b^2 > 16
a=0: intersect
b=0: the circle does not intersect
INSUFF

2. a = |b| + 5 ==> a>5>4 the circle does not intersect
SUFF
CEO
Joined: 21 Jan 2007
Posts: 2598
Location: New York City

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28 Nov 2007, 22:37
walker wrote:
B.

(x-a)^2 + (y-b)^2 = 16 means circle in center (a,b) and radius of 4.

1. a^2 + b^2 > 16
a=0: intersect
b=0: the circle does not intersect
INSUFF

2. a = |b| + 5 ==> a>5>4 the circle does not intersect
SUFF

can you elaborate on 1? why do we set them to zero
CEO
Joined: 17 Nov 2007
Posts: 3438
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

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28 Nov 2007, 22:51
bmwhype2 wrote:
can you elaborate on 1? why do we set them to zero

a=0: intersect - Distance of circle center to Y-axis is minimum - 0
b=0: the circle does not intersect - Distance of circle center to Y-axis is maximum - b
Intern
Joined: 25 Nov 2007
Posts: 37

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29 Nov 2007, 07:15
Walker can you explain how do you know its an equation for a circle? Are there particular equations to look for so we know if they are triangles, circles, rectangles??
CEO
Joined: 21 Jan 2007
Posts: 2598
Location: New York City

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29 Nov 2007, 14:09
shubhampandey wrote:
Walker can you explain how do you know its an equation for a circle? Are there particular equations to look for so we know if they are triangles, circles, rectangles??

http://www.analyzemath.com/CircleEq/Tutorials.html
CEO
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Posts: 3438
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
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29 Nov 2007, 14:18

we have a center of a circle - (a,b)
for any point (x,y) distance between (x,y) and the center must be constant (r -radius).

So, r^2=(x-a)^2+(y-a)^2 for any point on the circle. It is simply Pythagorean theorem.
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Posts: 9429
Re: Does curve (x-a)^2 + (y-b)^2 = 16 intersect the Y axis? 1.  [#permalink]

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19 Dec 2017, 10:38
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Re: Does curve (x-a)^2 + (y-b)^2 = 16 intersect the Y axis? 1. &nbs [#permalink] 19 Dec 2017, 10:38
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