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beyondinfinity
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v1rok
The correct answer is (D): each statement alone is sufficient

shahnandan correctly explained how to get to the value of BAO from the second statement. Here is how it can be deducted from the first statement:

Let's denote the unknown angle BAO as X. Then since AB=OC=OB, the angle AOB should also be X.

Next, from triangle ABO, angle ABO=180-(X+X)=180-2X

Therefore, angle OBC = 180 - angle ABO = 2X

But since OB=OC, angle BCO=2X

Now, we can have 2 equations for anle BOC:

First, from triangle BOC, angle BOC=180-(2X+2X)=180-4X

On the other hand, since angle AOD=180 and angle COD=60 (given),
angle BOC = 180 - (X+60)

So, 180 - 4X = 180- (X+60)

or, 3X=60

or, X=20


Great explanation. D is right.
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D it is.

St1: Since stem says AB=OB=OC

Lets say BAO = x
AOB = x (because AB=OB)
ABO = 180-2x (Triangle AOB)

Then OBC = 180-(180-2x) = 2x
BCO = 2x (Because OB = OC)
BOC = 180-2x-2x = 180-4x (Triangle BCO)

AOD = AOB + BOC + COD
180 = x + 180-4x + 60
Solving we get x = 20

St2: As explained by shahnandan.
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Given
AB = OC hence <BAO = <BOA -eq1
OC = OB (radius) hence <OBC = <OCB -eq2

1) <COD = 60

<COD = <OCA + CAO (sum of opposite interior angles = exterior angle)

From eq2
<COD = <CAO + < OBC
=> <COD = <CAO + (<CAO+<AOB ) {sum of opposite interior angles = exterior angle}

From Eq1
=> <COD = 3<CAO
Hence <CAO = 20

2) Same thing as above , here we know <OCA
Hence D
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parvathaneni
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gr8 explanations i too go with D
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rbcola
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This seems to be a 900 level problem. I was able to solve it, but took over 5 minutes. Was it worth it ?



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