DS_Boxes_number

Question

Please let know your brief explanations to the answer
thanks!

bkk145 · Answer

Got A.

total of 126 pots can be divided into 21 of 6 block of pots.

A

(1) If he uses fewer than 4 small boxes, he must use 3, 2, 1, or 0
With 3 small boxes, you will end up with 18 of 6 block of pots. This number is not divisible by 4.
With 2 small boxes, you will end up with 19 of 6 block of pots. This number is not divisible by 4.
With 1 small boxes, you will end up with 20 of 6 block of pots. This number IS divisible by 4.
With 0 small boxes, you will end up with 21 of 6 block of pots. This number is not divisible by 4.
This means he can only use 1 small box.
SUFFICIENT.

(2) INSUFFICIENT since the block of pots can be divide in any way.

IrinaOK · Answer

My answer was B,  the OA is D, 

Due to your post i found my mistake. 

1-st suff, just as you explained above {my mistake was to think that it is not the SMAL boxes, but BIG boxes, whose number is less than 4}

2-nd suff, he can use only 5 or 6 of big boxes, cuz 7*24 is more than 126
if he uses 5, then rest is divisible by 6 *editted
if he uses 6, then rest is not divisible by 6

Thank you,

carpeD · Answer

How can he use 6 big boxes ?? 6*24 = 144 ..

He can only use 5 big boxes.

similarly in statement 1 he can use only one small box else he would have to use 5 small boxes

so both statements are individually sufficient.

sujitmgmat · Answer

I did it like this. 

24B + 6S = 126
Therefore, 6B + S = 21. 

(1) implies S = 1 and, therefore, B = 5
(2) implies B = 5, therefore, S = 1. 

So each statement is SUFF.

jamesrwrightiii · Answer

This one was easy once you see the trick
Was this GMAT Prep or some other source?

DS_Boxes_number

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