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31 Oct 2004, 16:50
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This is an old question I found quite interesting and definitely within the GMAT realm.
If (3^4n) +1 is divided by 10, is the remainder 0?
a) n=2m+1, m is a positive integer
b) n> 4
If (3^4n) +1 is divided by 10, is the remainder 0?
a) n=2m+1, m is a positive integer
b) n> 4
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
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31 Oct 2004, 17:45
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Paul
(3^4n) + 1 = (81^n) + 1.
So no matter what the value of n is, the last digit of 81^n will always be 1. After adding 1 to it, it will be always 2. So it is never divisible by 10. I really haven't started tackling the DS questions yet, so I don't know the options.
31 Oct 2004, 19:56
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3^4n = 81^n
Any digit ending in 0,1,5,6 as the base number, then for all values of power, the number contains the same digit in the unit place. In this case it would be 1. 81^n +1 would mean that the unit place will become 2.
Divisibiliy by 10 is that the last number should be 0. In this case since the last digit is 2 it would not be divisible by 10.
So, D.
Any digit ending in 0,1,5,6 as the base number, then for all values of power, the number contains the same digit in the unit place. In this case it would be 1. 81^n +1 would mean that the unit place will become 2.
Divisibiliy by 10 is that the last number should be 0. In this case since the last digit is 2 it would not be divisible by 10.
So, D.
