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25 Mar 2008, 13:31
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w+x0 ?
(1) x+y<0
(2) y<x<w
Please advise the most optimal way to solve this problem. It took me some time to get correct answer.
(1) x+y<0
(2) y<x<w
Please advise the most optimal way to solve this problem. It took me some time to get correct answer.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
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25 Mar 2008, 14:50
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Statement 1:
Tells us x+y is -ve. Now both x and y can be -ve. Or one of them can be -ve and the -ve quantity will have greater magnitude. However there magnitude is not give. So this statement alone is not sufficient.
Statement 2:
Tells us w is more than x and x is more than y.
say x=y+k (where k is +ve as x is greater than y).
Given in question w+x = w+y+k < 0 => w+y < -k
So w+y>0 is not true.
B alone can answer the question.
Answer B.
Tells us x+y is -ve. Now both x and y can be -ve. Or one of them can be -ve and the -ve quantity will have greater magnitude. However there magnitude is not give. So this statement alone is not sufficient.
Statement 2:
Tells us w is more than x and x is more than y.
say x=y+k (where k is +ve as x is greater than y).
Given in question w+x = w+y+k < 0 => w+y < -k
So w+y>0 is not true.
B alone can answer the question.
Answer B.
25 Mar 2008, 19:47
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az780
W>Y ?
1.
1.1
-3 - 5 <0
-5 -4<0
-3>-4 CORRECT
1.2
-3 -3/2 <0
-3/2 -1<0
-3 NOT > -1 FALSE
1 INSUFFICIENT
2. W>Y: NO DISCUSTION
