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sidbidus
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KillerSquirrel
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Vemuri
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Vemuri
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Vemuri
Answer is D. Both statements are sufficient to answer the DS with a thumping yes :-)

Statement I says that (3r+2-s)(4r+9-s)=0. From this you can determine the values of r & s. r=-7; s=-19. Substituting these values in the line equation y=3x+2 satisfies it. Hence it is sufficient.

Statement II is similar to statement one & is sufficient to answer the question.

Hence answer is D. Correct me if I am wrong.



:cry: Ooppss.....I got into the GMAC trap. The correct answer should be C as KillerSquirrel rightly pointed in the links he provided for reference. Thanks for the question. I need to be more wary.
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Amardeep Sharma
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Answer C

1 is not sufficient as we are getting 2 different equations.

2. is not sufficient as we are getting 2 different equations.

solving both we will get the first equation = 12r ^2 + s^2 + 35r -11s -7rs +18 = 0

Second equation. 12r^2 + s^2 -10r+4s-7rs-12=0

on solving we will get s = 3r +2, which is the equation of the straight line mentioned above.

Amardeep
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GK_Gmat
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Getting C.

If the line y=3x+2 contains (r,s) then r, s must satisfy the equation of the line (in other words we should be able to substitute r for x and s for y).

If we assume that r,s lie on the line then s = 3r + 2 or 3r + 2 - s = 0. So the question is basically asking whether 3r + 2 - s = 0.

Stat 1: 3r+2-s could be 0 or 4r+9-s could be 0. Insuff.

Stat 2: 4r-6-s could be 0 or 3r+2-s could be 0. Insuff.

Together: If 3r+2-s is not equal to 0 in both statements then, 4r+9-s = 0 in the stat 1 and 4r-6-s = 0 in stat 2. Hence:
4r - s = 9 from stat 1 and 4r - s = 6 from stat 2. But this is not possible (since 4r-s cannot assume two different values). Thus, 4r+9-s cannot be 0 and therefore, 3r+2-s must be 0. Suff.



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