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# DS question from arjtryarjtry

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Director
Joined: 27 May 2008
Posts: 541

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23 Jul 2008, 08:49
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arjtryarjtry wrote:
can u help me out with this, in cartesian coordiates?
if x and y are +ve nos. is x>y?
1) x+y<1
2) y>x^2/2.
when a quadratic eqn is given, how does one solve using cartesian coordinates?

good question. you just need to draw three graphs.
First we have only +ve x and y, so we need to consider Q1 only.

target area is x > y means, area right of line x=y

st1. the small triangular area between lina x+y =1, x axis and y axis ...not suff
st2 : area above the graph y = (x^2)/2 ... not suff

combine : area within the small triangle mentioned above but above the graph ... still we can have a point on both sides of line x=y.. not suff

E

Attachment:

graph.JPG [ 21.99 KiB | Viewed 870 times ]

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Director
Joined: 27 May 2008
Posts: 541

Kudos [?]: 363 [0], given: 0

Re: DS question from arjtryarjtry [#permalink]

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25 Jul 2008, 02:38
i hope i'm right,
arjtryarjtry : whats the OA

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Current Student
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Schools: INSEAD Class of July '10
Re: DS question from arjtryarjtry [#permalink]

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25 Jul 2008, 02:58
Except that you did not plot y=x^2/2 (which is not affine by part), you are right

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Current Student
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Re: DS question from arjtryarjtry [#permalink]

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25 Jul 2008, 03:54
well, will post it ... i seem to have lost it. will get back. gimme some time pls

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Re: DS question from arjtryarjtry   [#permalink] 25 Jul 2008, 03:54
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