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mirhaque
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ds: sequence 04 Apr 2005, 17:39
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plz explain



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ds: sequence 04 Apr 2005, 20:19
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Ans is 'D'

Stmt 1 -
Let F4 = 5, F2 = 2, F6 = 3
N= 523523 --> is divisible by 7

If N = 438438 --> this is alos divisible by 7
This shld be true for all other cominations also.
Stmt 1 is sufficient

Stmt 2:
N = 1111111
This is divisible by 7.
-> Any multiple of N will be divisible by 7
Stmt 2 is sufficient

Ans = 'D'
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ds: sequence 04 Apr 2005, 20:33
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ssap
Ans is 'D'

Stmt 1 -
Let F4 = 5, F2 = 2, F6 = 3
N= 523523 --> is divisible by 7

If N = 438438 --> this is alos divisible by 7
This shld be true for all other cominations also.
Stmt 1 is sufficient

Stmt 2:
N = 1111111
This is divisible by 7.
-> Any multiple of N will be divisible by 7
Stmt 2 is sufficient

Ans = 'D'
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How did you take values for the statement1? Please explain
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MA
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ds: sequence Updated on: 05 Apr 2005, 17:28
Originally posted by MA on 04 Apr 2005, 20:55.
Last edited by MA on 05 Apr 2005, 17:28, edited 1 time in total.
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oh, it is D, mis-calculations.
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ds: sequence 05 Apr 2005, 07:22
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Assume value for F(1), F(2), F(3) etc.
Since no restrictions are given, except that N is a 6 digit integer number, assume integer values for each of those.
+ve or -ve does not matter as this problem tests only divisibility rules.
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ds: sequence 05 Apr 2005, 07:39
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(1) F(1)=F(4), F(2)=F(5), F(3)= F(6)
N=F(1)*100,000+F(2)*10,000+ ... +F(6)
=1001*(F(4)+F(5)+F(6))
1001/7=143 divisible by 7
Therefore N is divisible by 7

(2) is a special case of (1) So N is also divisible by 7.

(D)
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ds: sequence 05 Apr 2005, 11:17
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it should be E

because how do we know that in statement 1 all numbers are distinct??
i mean if F4=5 then F2=5 as well, we dont know right???

so the number could 555555? is that divisible by 7?
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ds: sequence 05 Apr 2005, 15:35
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HongHu
(1) F(1)=F(4), F(2)=F(5), F(3)= F(6)
N=F(1)*100,000+F(2)*10,000+ ... +F(6)
=1001*(F(4)+F(5)+F(6))
1001/7=143 divisible by 7
Therefore N is divisible by 7

(2) is a special case of (1) So N is also divisible by 7.

(D)
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I thought NF(k) was the number format....Now I got it
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ds: sequence 06 Apr 2005, 13:50
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How did you get this? Pls explain:
HongHu
N=F(1)*100,000+F(2)*10,000+ ... +F(6)
=1001*(F(4)+F(5)+F(6))
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ds: sequence 06 Apr 2005, 17:26
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mirhaque
How did you get this? Pls explain:
HongHu
N=F(1)*100,000+F(2)*10,000+ ... +F(6)
=1001*(F(4)+F(5)+F(6))
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option 1 says F4=F1

Since F4 is mutiplied by 1000 and F1=F4(given)

1000F4 + F1 = 1001F4 (Since F1=F4)
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ds: sequence 06 Apr 2005, 18:19
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ohh my bad
i realized these are digits in a number.....they cant be the same!

D it is...
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ds: sequence 07 Apr 2005, 10:31
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They CAN be the same. 555555 is divisible by 7.



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