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mirhaque
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mirhaque
can you pls explain the logic?


I am not sure, but I think its C.

Combing both statements together.

A(2) = 5 , A(1) -A(2) = 5 ==> A(1) = 10

Per defn A(n) = A(n-1)/n ==> A(3) = A(2)/3 or A(3) = 5/3 = 1.66

Simillarly A(4) = A(3)/4 ==> A(4) = 1.66/4 = .415

The series is a decreasing series, 10,5,1.66,.415,....

Hence I think C is the correct answer. Please let me know.

Thanks
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MA
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mirhaque
I am a bit lost. How do you find elements in the series bigger than 1/2? please explain the logic.. thanx.

give that, An=A(n-1)/n. remember that if the above eq is true,
A2=A1/2, A3=A2/3, A4=A3/4 and so on.........

from i, A2=5
A1/2=5
A1=10
If A1=10, A2=5, A3=5/3, A4=5/4 and so on.

from ii, A1-A2=5
A1-A1/n=5
A1-A1/2=5
2A1-A1 = 5
A1=10
If A1=10, A2=5, and as above....... hope that works.
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MA
mirhaque
I am a bit lost. How do you find elements in the series bigger than 1/2? please explain the logic.. thanx.
give that, An=A(n-1)/n. remember that if the above eq is true,
A2=A1/n, A3=A2/3, A4=A3/4 and so on.........

from i, A2=5
A1/2=5
A1=10
If A1=10, A2=5, A3=5/2, A4=5/4 and so on.


MA, you are absolutely correct with the solution,.

However, there is a small mistake, A3 = A2/3 and hence A3 = 5/3 and not 5/2, same applies to A4 as well. But this doesn't matter in a DS question.
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MA
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krisrini
MA
mirhaque
I am a bit lost. How do you find elements in the series bigger than 1/2? please explain the logic.. thanx.
give that, An=A(n-1)/n. remember that if the above eq is true,
A2=A1/n, A3=A2/3, A4=A3/4 and so on.........

from i, A2=5
A1/2=5
A1=10
If A1=10, A2=5, A3=5/2, A4=5/4 and so on.

MA, you are absolutely correct with the solution,.

However, there is a small mistake, A3 = A2/3 and hence A3 = 5/3 and not 5/2, same applies to A4 as well. But this doesn't matter in a DS question.


thanx.. i am correcting the same/.



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