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Bunuel
Each of the four identical containers (A, B, C and D) contains ‘b’ balls. When some of the balls from container A are moved to the other 3 containers, the ratio of the number of the balls in A,B,C and D are in the ratio 1:4:4:3. How many balls are moved from the first container in terms of ‘b’?

A. \((\frac{5}{6})b\)

B. \((\frac{1}{6})b\)

C. \((\frac{1}{3})b\)

D. \((\frac{2}{3})b\)

E. \((\frac{1}{2})b\)




Are You Up For the Challenge: 700 Level Questions

Let's assume that each container initially had "b" balls each, and "x" balls were removed from container A, leaving it with 'b-x' balls. We need to find the value of x.

The ratio of balls in A, B, C, and D after removing x balls from A = 1:4:4:3
Remaining balls in A = b-x
Therefore, the balls remaining in each container is b-x, 4(b-x), 4(b-x), and 3(b-x);

Total balls = 4b (b in each)
b-x + 4(b-x) + 4(b-x) + 3(b-x) = 4b
12b - 12x = 4b
-12x = -8b
x = 2b/3.

Hence, 2b/3 balls were removed from container A.
IMO (D) is the answer.
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