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kevincan
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I'm not sure if this is a trick, but just reading the question and statements tells us from Piglet A, there is no way we can tell how many piglets there are.

Click E and carry on to the next question.
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kevincan
Each piglet in a litter is fed exactly one-half pound of a mixture of oats and barley. The ratio of the amount of barley to that of oats varies from piglet to piglet, but each piglet is fed some of both grains. How many piglets are there?

(1) Piglet A was fed exactly 1/4 of the oats today.
(2) Piglet A was fed exactly 1/6 of the barley today.


definitely there are 4 piglets but could be more than 4.
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kevincan
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OA=C There must have been 5 piglets
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I agree with 'C'.

Statement1: This gives information about the Oats only. We are not sure how much was the Barley's proportion. So INSUFF

Statement2: Same as above. It doesn't give info about the oats' proportion.

Taking them together:

let total number of piglets are p
Total quantity of oat = x
Total quantity of barley= y
Putting the both statements in equation,
for one piglet
x/4+ y/6 = 1/2 it can be written as
9x + 6y = 18 ------------------(1)

remaining piglets = p -1
p-1 piglets are left with 3x/4 of oats and 5y/6 of barley.
putting in eq. 3x/4 + 5y/6 = (1/2)(p-1)
solving it, 9x +10y = 6p -6 ---------(2)

Solving eq 1 and 2
p = (2y/3) + 4

It means the piglets will be more than 4.
as p is a +ve integer, 2y/3 will be +ve integer. possible values of y = 1.5,3,4.5,6....
from equation1 6y < 18
hence y < 3
so y is 1.5.

That means total number of piglets = 1 + 4 = 5
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This is fabulous! Another way to is realise that A must get greater than the average quantity of oats and less than the average quantity of barley or vice versa



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