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tarek99
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x97agarwal
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tarek99
nope ;) you're wrong!

I possibly found my error and edited my answer. IMO C
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x97agarwal
lets the total amount of oats = x
and the amount of barley = y

S1. Piglet A was fed x/4; not enough information AD out

S2. Piglet A was fed y/6; not enough information B is out

Combining: x/4 + y/6 = 1/2 ;
3x + 2y = 6
x and y cannot be -ve or zero
Hence for this equation to hold: x = 1 and y = 1.5 (3+3 = 6)

IMO C

Although C is the OA, you didn't give the total number of piglets. According to your variables, X and Y are the amounts of oat and barely respectively, but they are NOT the number of piglets. So what's the number of piglets?
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x97agarwal
lets the total amount of oats = x
and the amount of barley = y

S1. Piglet A was fed x/4; not enough information AD out

S2. Piglet A was fed y/6; not enough information B is out

Combining: x/4 + y/6 = 1/2 ;
3x + 2y = 6
x and y cannot be -ve or zero
Hence for this equation to hold: x = 1 and y = 1.5 (3+3 = 6)

IMO C

Although C is the OA, you didn't give the total number of piglets. According to your variables, X and Y are the amounts of oat and barely respectively, but they are NOT the number of piglets. So what's the number of piglets?

Sorry I forgot.
6kg of total feed; since each piglet is give 0.5kg the total number should be 6/0.5 = 12
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but then for some reason, the explanation says that the number of piglets should be 5??? here's how:

We know that each piglet is fed \(1/2\) pound of oats and barely, so each piglet receives either an above average amount of oats and a below average amount of barely, vice versa, or even an average amount of both grains. Neither (1) nor (2) is sufficient by itself, but together, we see that piglet A got a larger share of that oats and a below average amount of barely. (1) tells us that there are more than 4 piglets and (2) tells us that there are fewer than 6 piglets. Thus there are \(5\) piglets.

More mathematically, suppose there are x piglets sharing a total of B pounds of barely and O pounds of oats. Each piglet then receives \((B+O)/x\) pounds of grain. Piglet A received received \(O/4 + B/6\) pounds of grain.

Therefore, \((B+O)/x = (3O+2B)/12\) and \(x/(B+O) = 12/(3O+2B)\)



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