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Tough and Tricky questions: Word Problems.

Each week a restaurant serving Mexican food uses the same volume of chili paste, which comes in either 25-ounce cans or 15-ounce cans of chili paste. If the restaurant must order 40 more of the smaller cans than the larger cans to fulfill its weekly needs, then how many smaller cans are required to fulfill its weekly needs?

Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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01 Dec 2014, 05:53

let x be the number of 25 ounce cans. Therefore (x+40) is the number of 15 ounce cans. Total volume is same, therefore 25x=15(x+40) 10x=600 x=60 Therefore, number of 15 ounce cans=60+40=100

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01 Dec 2014, 18:13

From this question we know that there are 40 more 15oz cans then 25oz cans needed for an equivalent amount of the recipe. This means that 15*x or the number of 15 oz cans needed is equal to 25(x-40) or the number of 25oz cans needed. Let's equate these two expression:

Each week a restaurant serving Mexican food uses the same volume of chili paste, which comes in either 25-ounce cans or 15-ounce cans of chili paste. If the restaurant must order 40 more of the smaller cans than the larger cans to fulfill its weekly needs, then how many smaller cans are required to fulfill its weekly needs?

Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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16 May 2016, 11:42

consider the number of 15 ounce small cans be x so the number of large 25 ounce cans is (x - 40) as the difference between number of small cans and large cans is 40

But we are given that the restaurant uses same volume of chili paste - either from 25 ounce cans or 15 ounce cans So the quantity obtained from either of them must be same

15 * x = 25 * (x - 40) 10 * x = 1000 x = 100

therefore 100 smaller cans are required to fulfill its weekly needs correct answer - D

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13 Jul 2017, 11:28

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Each week a restaurant serving Mexican food uses the same volume of chili paste, which comes in either 25-ounce cans or 15-ounce cans of chili paste. If the restaurant must order 40 more of the smaller cans than the larger cans to fulfill its weekly needs, then how many smaller cans are required to fulfill its weekly needs?

A) 60 B) 70 C) 80 D) 100 E) 120

If we let the number of large cans = x, then the number of smaller cans = x + 40. The total volume of the large cans is 25x, which is equal to the total volume of the smaller cans, 15(x + 40).

We can now create the following equation to determine x:

15(x + 40) = 25x

15x + 600 = 25x

600 = 10x

60 = x

Thus, the number of small cans needed is 60 + 40 = 100.

Answer: D
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GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions

Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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18 Aug 2017, 01:49

Using Options. Starting from middle option C: Small =80 so big =40 qty : 80*15 = 1200,40*25 = 1000 Since we need more larger cans, therefore moving downward to option D D: Small =100 so big =60 qty : 100*15 = 1500, 60*25=1500

Thus option D is correct
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Abhishek Parikh Math Tutor Whatsapp- +919983944321 Mobile- +971529685639 Website: http://www.holamaven.com

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