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Each week a restaurant serving Mexican food uses the same volume of ch

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New post 01 Dec 2014, 05:34
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Tough and Tricky questions: Word Problems.



Each week a restaurant serving Mexican food uses the same volume of chili paste, which comes in either 25-ounce cans or 15-ounce cans of chili paste. If the restaurant must order 40 more of the smaller cans than the larger cans to fulfill its weekly needs, then how many smaller cans are required to fulfill its weekly needs?

A) 60
B) 70
C) 80
D) 100
E) 120

Kudos for a correct solution.

Source: Chili Hot GMAT
[Reveal] Spoiler: OA

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Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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New post 01 Dec 2014, 05:53
let x be the number of 25 ounce cans. Therefore (x+40) is the number of 15 ounce cans.
Total volume is same, therefore
25x=15(x+40)
10x=600
x=60
Therefore, number of 15 ounce cans=60+40=100

Ans - D

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New post 01 Dec 2014, 18:13
From this question we know that there are 40 more 15oz cans then 25oz cans needed for an equivalent amount of the recipe. This means that 15*x or the number of 15 oz cans needed is equal to 25(x-40) or the number of 25oz cans needed. Let's equate these two expression:

15x = 25(x-40)
15x = 25x - 1000
10x = 1000
x = 100 (100 15oz cans required)

Choice D

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Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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New post 01 Dec 2014, 21:01
Answer = D = 100

Say "x" cans are procured

We require to find x+40

25x = 15(x+40)

x = 60

x+40 = 100
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Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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New post 16 May 2016, 11:42
consider the number of 15 ounce small cans be x
so the number of large 25 ounce cans is (x - 40) as the difference between number of small cans and large cans is 40

But we are given that the restaurant uses same volume of chili paste - either from 25 ounce cans or 15 ounce cans
So the quantity obtained from either of them must be same

15 * x = 25 * (x - 40)
10 * x = 1000
x = 100

therefore 100 smaller cans are required to fulfill its weekly needs
correct answer - D

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Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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New post 13 Jul 2017, 14:22
Volume x, then number of big cans and small cans:
x/25 = x/15 + 40.

Then x/25 - x/15 = 40 >> 3x/75 - 5x/75 = 40
Then 2x/75=40 >> 2x = 3000, x = 1500, so 60 big cans or 100 small cans

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Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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New post 16 Jul 2017, 17:34
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Quote:

Each week a restaurant serving Mexican food uses the same volume of chili paste, which comes in either 25-ounce cans or 15-ounce cans of chili paste. If the restaurant must order 40 more of the smaller cans than the larger cans to fulfill its weekly needs, then how many smaller cans are required to fulfill its weekly needs?

A) 60
B) 70
C) 80
D) 100
E) 120



If we let the number of large cans = x, then the number of smaller cans = x + 40. The total volume of the large cans is 25x, which is equal to the total volume of the smaller cans, 15(x + 40).

We can now create the following equation to determine x:

15(x + 40) = 25x

15x + 600 = 25x

600 = 10x

60 = x

Thus, the number of small cans needed is 60 + 40 = 100.

Answer: D
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Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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New post 18 Aug 2017, 01:49
Using Options. Starting from middle option
C: Small =80 so big =40
qty : 80*15 = 1200,40*25 = 1000
Since we need more larger cans, therefore moving downward to option D
D: Small =100 so big =60
qty : 100*15 = 1500, 60*25=1500

Thus option D is correct
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Re: Each week a restaurant serving Mexican food uses the same volume of ch [#permalink]

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New post 03 Dec 2017, 23:07
Hi All,

This question question is an example of a 'system' algebra question - but it can actually be solved in a variety of different ways, including Algebraically and by TESTing THE ANSWERS. If you recognize the ratio that exists begin the two sizes of cans, then you can also use that pattern to your advantage...

6 (25-ounce cans) = 150 ounces
10 (15-ounce cans) = 150 ounces

You can use THAT ratio (6:10) to work through this question relatively quickly...
6 and 10 = 4 more of the smaller cans
12 and 20 = 8 more of the smaller cans
18 and 30 = 12 more of the smaller cans
Etc.

We're told that the number of smaller cans that are needed would be 40 more than the number of larger cans. That would be...
6(10) and 10(10) =
60 and 100 = 40 more smaller cans

100 smaller cans would be needed

Final Answer:
[Reveal] Spoiler:
D


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Kudos [?]: 3676 [0], given: 173

Re: Each week a restaurant serving Mexican food uses the same volume of ch   [#permalink] 03 Dec 2017, 23:07
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