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Each year for 4 years, a farmer increased the number of trees in a

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Re: Each year for 4 years, a farmer increased the number of trees in a  [#permalink]

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New post 04 Nov 2018, 02:28
yashna36 wrote:
Hi,

I tried using geometric progression formula for this ->
x is the no of trees at the end of 1st year, end of 2nd year no of trees is 5x/4. Therefore, common ratio (r) is 5/4

6250=x(r^n-1)
6250= x(5/4)^4-1
6250=x(5/4)^3
x=(6250*64)/125
x=3200

can you please explain to me where has my reasoning gone wrong?


Hey yashna36,
There is nothing wrong in your reasoning - you need to do one more step to get the final answer.

You have assumed x as the number of trees at the end of 1st year, whereas the question is asking us to find the number of trees at the beginning of the 1st year.

Therefore, you need to divide 3200 by 5/4 to get the final answer.

Hope this helps. :)
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Re: Each year for 4 years, a farmer increased the number of trees in a  [#permalink]

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New post 04 Nov 2018, 11:09
It's a compound interest with rate = 25% , time = 4 year.

6250 = x (1+ 25/100)^4

x = 2560
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Re: Each year for 4 years, a farmer increased the number of trees in a &nbs [#permalink] 04 Nov 2018, 11:09

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Each year for 4 years, a farmer increased the number of trees in a

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