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Thanks..I'm able to follow the equations. The one place I'm confused is at the beginning. How did you get 2/3(C)? Is the 2/3 a default formula?[/b]
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when you have a square inscribed inside a circle it will divide the circumface into 4 equal diffrent segments. the same goes for a triangle inscibed inside a circale it will divide the circumface into 3 equal segments.
knowing that 2 segments equal 24 we can find the circumface of the circale.
I think I follow...so for a triangle..if a triangle is inscribed into a circle the we have 3 equal parts. Since ABC=24 we have 2/3 = 24.
So If we have ABC equal to 50 would we have 2/3= 50 or a different number.
Also when we have a square. We would have 4 equal parts. And let's assume that Arc ABCD = 24 would we have 3/4 = 24 or is the ratio different for a square?
Awsome explanation Killer squirrel. One question. Why do we only know 2 of the sides? When u say length ABC is that only 2 sides? Like literally A to B then B to C, which would kinda look like this:
^
(sorry that is not bigger).
If this is true, then I get the whole damn problem and understand why u had to do 3/2 for 36. Although since its equilateral not sure if u have to.
good stuff....I was going for the complicated method of using the r*(theta) = arc length
the proped method didnt occur to me...now I will remember...thanks
Yes ! in order to solve the given problem, the triangle has to be equilateral ! For a square it's the same princeple , instead of dividing the circle circumface into three segments it will divided it into four smaller then 12 segments (of 9).
please note that it has to be a square ! a rectangular won't do the trick !
thanks all
:-D
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