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Every month, Mary and Helen shared month rent of $1,000, by

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Joined: 11 May 2008
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Every month, Mary and Helen shared month rent of $1,000, by [#permalink]

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New post 25 Jul 2008, 18:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Every month, Mary and Helen shared month rent of $1,000, by the same ratio from their monthly salary. In May, Helen's salary is $4,000. Mary switched her job in June and earned a different salary, while Helen's salary remained unchanged. What's the difference between the salary of Mary's old and new job?

(1) Helen paid 15% of her salary for the rent in May.
(2) Mary paid total $450 for the rent in June.

A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

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Director
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Re: salaries [#permalink]

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New post 25 Jul 2008, 18:33
arjtryarjtry wrote:
Every month, Mary and Helen shared month rent of $1,000, by the same ratio from their monthly salary. In May, Helen's salary is $4,000. Mary switched her job in June and earned a different salary, while Helen's salary remained unchanged. What's the difference between the salary of Mary's old and new job?

(1) Helen paid 15% of her salary for the rent in May.
(2) Mary paid total $450 for the rent in June.

A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.


Mary's old job: x, new job x + y -> looking for y
1) Helen paid 15% of her salary of 15%*4,000 = 600-> insufficient -> no info about y, but x = (1,000-600)/15%=400/15% = (2/3)*(4,000)
2) Mary paid $450 -> x + y = (45/55)*(4,000) -> insufficient because y is unknown

1&2: sufficient y = (x+y)-x = (45/55)*4,000-(2/3)*4,000 -> sufficient -> C

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Senior Manager
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Re: salaries [#permalink]

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New post 25 Jul 2008, 18:40
I'd go for C.

From stem:
May salaries: Helen = 4K; Mary ?
June: Helen = 4K; Mary ?
Rent = 1K

(1) Helen paid 15% of her salary for the rent in May.
Helen paid 150 for rent, therefore, Mary paid 1000-150= 850 (talking about wage differences), which means she makes 5,666. No information about her new salary. INSUFF.

(2) Mary paid total $450 for the rent in June.
This is telling us Helen payed about 11% of her salary in rent, meaning Mary payed $550, or 11% of her new salary). However, we have no information about May. INSUFF.

(1+2) Information from both girls for both months. SUFF.

Kudos [?]: 57 [0], given: 1

Re: salaries   [#permalink] 25 Jul 2008, 18:40
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Every month, Mary and Helen shared month rent of $1,000, by

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