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kuharido
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nsp007
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nsp007
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kuharido
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Thanks, though i still didnt really understand

the problem on the exam is written as you typed, with the stuff between parenthesis in superscript, but the numbers in the denominator don't have any paranthesis, here is a better detail

Numerator : 2 superscript (4-1)^2

Denominator : 2 superscript 3-2

I am assuming the first superscript is a power, and ^ is a power of that, in that case, shouldn't the numerator be equal to

2^ 3 ^ 2 = 2^6 ?

and the denominator = 2^3-2 = 2^1 = 2 ?

2^6/2 = 2^5 shouldnt this be the answer ?
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kuharido
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Ok i got the average one, dont know why i averaged both values !

Its the first prep test i took and i got a 40q score without any studying or practise, i'm pretty bummed as I don't know by how many points would practise improve it anyways, it seemed like a you know it or you dont kind of thing
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kuharido
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Oh sorry ok, i got the exponents one as well now, jeez whats wrong with me

Thanks man i really appreciate it

So when its 2^3^2 i thought you multiply the exponents (3*2=6) and then it becomes 2^6 no ? am i wrong ? or is this case an exceptional notation ?
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nsp007
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I am assuming the first superscript is a power, and ^ is a power of that, in that case, shouldn't the numerator be equal to

2^ 3 ^ 2 = 2^6 ?


2^3^2 is not the same as (2^3)^2.

2^3^2 = 2^9
(2^3)^2 = 8^2 = 2^6

Hope this helps !
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kuharido
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It does, mega thanks friend
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Bunuel
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kuharido
Thanks, though i still didnt really understand

the problem on the exam is written as you typed, with the stuff between parenthesis in superscript, but the numbers in the denominator don't have any paranthesis, here is a better detail

Numerator : 2 superscript (4-1)^2

Denominator : 2 superscript 3-2

I am assuming the first superscript is a power, and ^ is a power of that, in that case, shouldn't the numerator be equal to

2^ 3 ^ 2 = 2^6 ?

and the denominator = 2^3-2 = 2^1 = 2 ?

2^6/2 = 2^5 shouldnt this be the answer ?

Solution provided by nsp007 is correct:

If exponentiation is indicated by stacked symbols, the rule is to work from the top down, thus:
\(a^m^n=a^{(m^n)}\) and not \((a^m)^n\), (\((a^m)^n=a^{mn}\)).

So \(2^{{(4-1)}^2}=2^{3^2}=2^9\).

Check Number Theory chapter of the Math Book for more on this issue (link in my signature).

Hope it helps.
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kuharido
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Bunuel thanks a lot, especially for the guide ! Actually I had already bookmarked that treasure of math knowledge but didn't get to review it, thank you

P.S "exponentiation" is fun to say :)
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kuharido
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I realize this isn't the best post to ask this on but, do you reckon an 8 point increase is within reach with proper practice (from 40 to 48) ? (I have about two months, can put in good hours every week)



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