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factorial question!

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Director
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factorial question! [#permalink]

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New post 20 Jul 2009, 20:00
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Could someone please explain how 2!=(m-1)!
= 2=m-1
= m=3?
i know the factorial concept as in 5!=5 x 4 x 3 x 2 x 1.The (m-1)! is the part that got me confused.
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Director
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Re: factorial question! [#permalink]

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New post 20 Jul 2009, 20:41
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tejal777 wrote:
Could someone please explain how 2!=(m-1)!
= 2=m-1
= m=3?
i know the factorial concept as in 5!=5 x 4 x 3 x 2 x 1.The (m-1)! is the part that got me confused.

Without knowing the context of your question, I'll have to just take a guess about what you're talking about.

It would appear that you might be describing a circular permutation.

Example: How many ways can you arrange 5 flowers in a circle?
Circular arrangements are always calculated as (n-1)!, where n is equal to the # of items, because the ends touching each other are double counted (ABCDE is the same arrangement as BCDEA in a circular arrangement).

If your question is simply: how can 2! = (m-1)!, then m equals 3.

If that doesn't answer your question, please provide more detail.
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Re: factorial question! [#permalink]

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New post 21 Jul 2009, 02:58
2!=(m-1)!
since the operators are same the expressions have to be same as well, 2=m-1 , m=3

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Re: factorial question! [#permalink]

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New post 21 Jul 2009, 16:52
Avernusaur remembered the circular permutation! good job. Have you already seen a question with that in GMAT? Could you post please?

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Re: factorial question!   [#permalink] 21 Jul 2009, 16:52
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