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# Factoring out a common term?

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Intern
Joined: 15 Oct 2017
Posts: 28
Schools: Northeastern '20
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23 Oct 2017, 22:52
11³+11⁴-->11³(11⁰+11¹)-->11³(1+11)-->11³(12)

Sorry guys, but I don't really understand that concept. Do you know more about it?

thank you
BSchool Forum Moderator
Joined: 26 Feb 2016
Posts: 2963
Location: India
GPA: 3.12
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24 Oct 2017, 05:43
Hi thegame12 ,

Welcome to GMATClub

$$11^3 + 11^4 = 1*11^3 + 11*11^3$$(One multiplied with any number gives the same number)

This can be further simplified by taking the common term outside.
We need to follow the ‎distributive law a·b+a·c = a·(b+c)‎

In this case the common term is 11^3 which if taken outside gives
$$1*11^3 + 11*11^3 = 11^3(1+11) = 11^3(12)$$

Hope that helps!
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Re: Factoring out a common term?  [#permalink]

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24 Oct 2017, 06:56
thegame12 wrote:
11³+11⁴-->11³(11⁰+11¹)-->11³(1+11)-->11³(12)

Sorry guys, but I don't really understand that concept. Do you know more about it?

thank you
pushpitkc has explained it, but are there any specific things here that you're not comfortable with? For example, are you okay "seeing" 11⁰ as 1 (any non-zero number raised to the power of 0 is 1)?
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Re: Factoring out a common term? &nbs [#permalink] 24 Oct 2017, 06:56
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# Factoring out a common term?

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