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Fanny and Alexander are y miles apart and are traveling in a straight 06 Dec 2018, 08:25
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66% (01:31) correct 34% (01:50) wrong based on 705 sessions

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Fanny and Alexander are y miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and x mph respectively. What is the value of x?

(1) 1.5 hours before they meet they were 135 miles apart
(2) y = 360 miles


M36-94

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Fanny and Alexander are y miles apart and are traveling in a straight 12 Nov 2021, 08:19
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Bunuel
Fanny and Alexander are y miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and x mph respectively. What is the value of x?

(1) 1.5 hours before they meet they were 135 miles apart
(2) y = 360 miles


M36-94
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Fanny and Alexander are \(y\) miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and \(x\) mph respectively. What is the value of \(x\)?

(1) 1.5 hours before they meet they were 135 miles apart

The combined rate of Fanny and Alexander is \(25+x\) mph and if 1.5 hours before they meet they were 135 miles apart, then in 1.5 hours together they should cover 135 miles: \((25+x)*1.5=135\) (rate*time = distance). We can find \(x\). Sufficient.

(2) \(y = 360\) miles. Clearly insufficient.


Answer: A
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Fanny and Alexander are y miles apart and are traveling in a straight 06 Dec 2018, 15:30
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Bunuel
Fanny and Alexander are y miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and x mph respectively. What is the value of x?

(1) 1.5 hours before they meet they were 135 miles apart
(2) y = 360 miles
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Statement 1: before they meet they are 135 miles apart, and they meet after 1.5 hours, so the distance between them/relative speed = time taken to meet. So, 135/(25+x)=1.5, x=65. Sufficient.

Statement 2, y = 360 miles, no information about x or time taken to meet each other. Insufficient.

IMO, A.
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Fanny and Alexander are y miles apart and are traveling in a straight 06 Dec 2018, 17:30
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Statement 1: Relative speed = (25+x) mph. Distance covered = 135 in 1.5 hrs. Hence, 135/(25+x)=1.5, x=65. Sufficient.

Statement 2: Relative speed = (25+x) mph. y = 360 miles but no information on time taken to meet each other. Insufficient.

Option: A
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Fanny and Alexander are y miles apart and are traveling in a straight 06 Dec 2018, 23:23
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Hi,

Given,

Speed of fanny = 25mph

Speed of alexander = “x” mph

Distance between them = “y” miles

Since both of them travelling towards each other (opposite directions), relative speed is sum of their speeds.

i.e., Every hour both will cover = (25+x) mph

Question: Speed of alexander = “x” mph ?

Statement I is sufficient:

1.5 hours before they meet they were 135 miles apart.

This tells the remaining time taken and the distance to cover.

i.e., both will travel 135 miles in 1.5 hours.

So, time = distance/ Speed

1.5 = 135/(25+x)

We can stop here, clearly there will be one value of “x”.

37.5 + 1.5x = 135.

x = 97.5/1.5

x = 65.

So sufficient.

Statement II is insufficient:

y = 360 miles.

Knowing only the distance doesn’t help here. We need to know the time.

So insufficient.

So the answer is A.

Hope this helps.

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Junaid.
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Fanny and Alexander are y miles apart and are traveling in a straight 24 Dec 2018, 01:18
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Bunuel
Fanny and Alexander are y miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and x mph respectively. What is the value of x?

(1) 1.5 hours before they meet they were 135 miles apart
(2) y = 360 miles
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Fanny and Alexander are y miles apart and are traveling in a straight 08 Oct 2019, 04:57
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Bunuel
Fanny and Alexander are y miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and x mph respectively. What is the value of x?

(1) 1.5 hours before they meet they were 135 miles apart
(2) y = 360 miles
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Given: Fanny and Alexander are y miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and x mph respectively.

Asked: What is the value of x?

(1) 1.5 hours before they meet they were 135 miles apart
Relative speed = 135/1.5 = 90 mph = 25 + x
x = 65 mph
SUFFICIENT

(2) y = 360 miles
NOT SUFFICIENT

IMO A
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Fanny and Alexander are y miles apart and are traveling in a straight 14 Apr 2024, 10:02
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Answer: alternative A


Explanation:


Since it is an example of a meeting, in opposite directions (one advances towards the other), the hour and a half remaining until the meeting between Fanny and Alexander must be traveled by both with their respective speeds and then you must add them.

ie) 65 x 3/2 + 25 x 3/2 = (65 + 25) x 3/2 = 90 x 3/2 = 135 miles.
 
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Fanny and Alexander are y miles apart and are traveling in a straight 25 May 2025, 01:26
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