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Bunuel

Figure ABCE is a trapezoid with ED = 5 and AB = 12. What is the area of the trapezoid?

(1) Angle ADE is 60 degrees.

(2) AD is parallel to BC.



Project DS Butler Data Sufficiency (DS3)


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Attachment:
1.png

From statement 1, we can find the value of AE which will be 5\sqrt{3}
From statement 2, we know that CD is equal to AB. CE = CD+DE = 17

Area of the trapezoid can be found out if we know the length of 2 parallel sides and the distance between them

Option C
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Area of trapezoid ABCE = 1/2 * AE * (AB + EC)

(1) Angle ADE is 60 degrees.
---> AD = 2 * ED = 12.
---> AE = √108.
---> Unable to calculate EC.
---> The area cannot be calculated.
=> Not enough.

(2) AD is parallel to BC.
---> ABCD is a parallelogram.
---> DC = AB = 12. ---> EC = 17.
---> Cannot calculate AE.
---> The area cannot be calculated.
=> Not enough.

(1) + (2) ---> AE = √108, EC = 17 and AB = 12.
---> Calculate the area.
=> Enough.

Answer: C.
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Given information

ABCE is a trapezoid
AB=12,ED=5

1) In Triangle AED
Angle ADE = 60, Therefore angle EAD = 30
Therefore sides ED:AE:AD is in the ratio 1:1.732:2

Therefore side AE = 5*1.732=8.67
Therefore area of triangle = 1/2* ED*AE=1/2*5*8.67=21.68
Area of the figure ABCD is not given and the given information is Insufficient to find the area

2) AD\\BC
Therefore area of the parallelogram ABCD is equal to AE*AB = 8.67*12=104.04
In the trapezium ABCE area of the triangle AED is not known.

Therefore statement 2 alone is insufficient to find the correct answer

Option C - statement 1+2 that is area of trapezium ABCE=Area of triangle AED+ Area of \\ ABCD=21.68+104.04

Sufficient

IMO C
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