Find an integer X

Question

some old merry question
Find an integer X.

(1) sqrt|X|=|X|! 
(2) |X|=sqrt|X|

mba · Answer

Not sure about this one,
A quick guess would be (D).
each of the statements lead to only one value of x that is 1.

Dookie · Answer

A.

1) Could only be x=1.
2) X=0,1,-1

mba · Answer

oops! my mistake,

It should be (A).
1) sufficient ---> 1
2) has possible values as 0,1 (-1 cannot be the value because sqrt(-1) is not 1)

cbrf3 · Answer

A sjould be it...........BTW I picked D too at first , but later noticed the modilus of X in the sqrt... :oops:

Anonymous · Answer

(1)

sqrt|-1|=|-1|!
sqrt(1) = 1!
1=1

sqrt|1|=|1|!
sqrt(1) = 1!
1=1

so it can be 1 or -1

(2)

sqrt|-1|=|-1|
sqrt(1) = 1
1=1

sqrt|1|=|1|
sqrt(1) = 1
1=1

so it can be 1 or -1

so it must be E. 

I'm wrong?

Paul · Answer

same as Alfred. I got E
1) -1 or 1
2) -1 or 1

manan · Answer

i concur with alfred n paul.

but in addition to -1,1 why can't we also have 0 as part of the solution set?

sqrt|(0)| = |0|! = 1

manan · Answer

o god!!! i've had enough for the day... making such stupid errors... i guess with 15 days to go for D-DAY the pressure's getting to me!

)

mba · Answer

How can you say sqrt(-1) = |-1|!.
SQRT(-1) is Imaginary number, while |-1|! is 1 a real number.
Hence it has to be (A).

Dookie · Answer

oops, forgot it was a square root of an absolute value. Must be E. :oops:

Dangerous question !!! :!:

afife76 · Answer

For (2)
sqrt|0|=|0|
0=0

is this wrong?

Paul · Answer

Afife, you're right for 2. 0 should be part of answer

stolyar · Answer

(1) X =   NOT SUFF
(2) X =   NOT SUFF

combine: X=  NOT SUFF

Therefore, E.

mba · Answer

Thanks for Paul for pointing out my mistake, must too drunk to miss this thing twice!!

 :drunk

Find an integer X

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