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virtualanimosity
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Find the 28383rd term of series 123456789101112..... 04 Nov 2009, 01:01
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

55% (hard)

Question Stats:

75% (00:12) correct 25% (01:56) wrong based on 4 sessions

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Find the 28383rd term of series 123456789101112.....

1. 3
2. 4
3. 9
4. 7

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A
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Find the 28383rd term of series 123456789101112..... 04 Nov 2009, 09:22
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virtualanimosity
Q.
Find the 28383rd term of series 123456789101112.....

1. 3
2. 4
3. 9
4. 7
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1-9 = 9 x 1 = 9 digits
10-99 = 90 x 2 = 180 digits
100-999 = 900x3 = 2700 digits
need = 28383 - 2889 = 25494 digits
need 25494/4 = 6373.50 more terms. wow... 0.5 terms? not possible. so we need to take 6374th term from 1000th term. i.e.

1000-7374 = 6374 terms x 4 = 25496 digits.
so altogather 1-7374 terms have 28385 digits. 28385th digit is 4, 28384th digit is 7 and 28383rd digit is 3. Thats A..
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Find the 28383rd term of series 123456789101112..... 19 Nov 2009, 21:17
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wow.. is this is real GMAT question? I was pondering so hard for short cuts but I guess the best way is to count it up...
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Find the 28383rd term of series 123456789101112..... 13 Feb 2011, 09:43
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Digit to be found: "28383"

One digit numbers: 9*1=9 digits
Two digit numbers: 90*2=180 digits
Three digit numbers: 900*3=2700 digits
Four digit numbers: 9000*4=36000 > more than 28383. So the digit got to be from a number less than a 5 digit numbers.

Digits used until the number 999: 9+180+2700 = 2889
Digit to be found: 28383
or
28383-2889 = 25494 digit from the first digit i.e. "1" of the number (1000)

Dividing it by 4 will give us the number's index in four digit numbers: 6373. Remainder 2.

"6373" numbers are fully utilized after 999.

999+6373 = 7372

Next number: 7373

The digit will be the second digit(Remainder: 2) of the number 7373.

Ans: "A"

Took almost 4 minutes to formulate and solve this. Yet, I am not too confident about its correctness.

Perhaps there is a better way to solve!!!
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KarishmaB
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Find the 28383rd term of series 123456789101112..... 13 Feb 2011, 22:21
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fluke
Digit to be found: "28383"

One digit numbers: 9*1=9 digits
Two digit numbers: 90*2=180 digits
Three digit numbers: 900*3=2700 digits
Four digit numbers: 9000*4=36000 > more than 28383. So the digit got to be from a number less than a 5 digit numbers.

Digits used until the number 999: 9+180+2700 = 2889
Digit to be found: 28383
or
28383-2889 = 25494 digit from the first digit i.e. "1" of the number (1000)

Dividing it by 4 will give us the number's index in four digit numbers: 6373. Remainder 2.

"6373" numbers are fully utilized after 999.

999+6373 = 7372

Next number: 7373

The digit will be the second digit(Remainder: 2) of the number 7373.

Ans: "A"

Took almost 4 minutes to formulate and solve this. Yet, I am not too confident about its correctness.

Perhaps there is a better way to solve!!!
Show more

Not a realistic GMAT question. Too many painful additions and subtractions. You will not find any question in OG that involves too many calculations. Even if it seems you need to calculate a lot in some questions, it will just be because you haven't seen a trick. Also, the question is kind of direct and straightforward. Terribly lacks the 'oomph' factor that tougher GMAT questions have. (If you like Math, you will end up enjoying your GMAT Quant section, whether you score well in it or not.)
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Find the 28383rd term of series 123456789101112..... 07 Aug 2021, 04:43
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