If we knew the area of the room, we could answer the question. I assume Statement 1 is trying to tell us we have a square-inside-a-square (the room is a square, then when we add on the veranda of uniform width, we get a larger square). Statement 1 tells us nothing about the size of the inside square, so isn't sufficient, and using only Statement 2, we again know nothing about the room (or even about what this veranda is, since we need to forget about Statement 1).
But using both statements, the larger the room, the larger the veranda will be, so there can only be one size of room that produces a veranda of 432 square meters, and the answer must be C. We don't need to solve anything, but if we wanted to, if the room's length is x, the veranda's is x+6 (it's extends 3 meters beyond the room in both directions). So the area of the veranda and room combined is (x+6)^2, and the area of the room is x^2, and the area only of the veranda is (x + 6)^2 - x^2 = (x + 6 + x)(x + 6 - x) = 6(2x + 6) = 12(x + 3), here using the difference of squares, and since this is equal to 432, we have
12(x + 3) = 432
x + 3 = 36
x = 33
So the area of the room is 33^2, and the cost at 25 Rs per square meter is 25*33^2.