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Find the least integral value of 'k' for which the equation

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Senior Manager
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Find the least integral value of 'k' for which the equation [#permalink]

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New post 30 Jan 2004, 10:52
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Find the least integral value of 'k' for which the equation
9x^2 + 6(k+2)x + (-8 + k^2) = 0 has two different real roots.

a.-4
b.0
c.-2
d.1
e. :fu
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New post 30 Jan 2004, 11:14
I choose E :twisted:

Is the answer A.

b^2-4AC must not be zero other wise the roots are equal.
For K = -3 the roots are equal. :( But that is not one of the
answer. So pick a least number and that is -4, choice A


Where did you get these damn questions?

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New post 30 Jan 2004, 16:21
b^2 - 4ac > 0

36(k+2)^2 - 36(-8+k^2) > 0
4k+12 > 0
k > -3

Answer is -2

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New post 30 Jan 2004, 16:36
Zhung Gazi
:yes
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Pls include reasoning along with all answer posts.
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Este examen me conduce jodiendo loco

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  [#permalink] 30 Jan 2004, 16:36
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Find the least integral value of 'k' for which the equation

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