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01 Sep 2010, 11:20
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
61% (01:38) correct
39%
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wrong
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A certain rectangular crate measures 8 feet by 10 feet by 12 feet. A cylindrical gas tank is to be made for shipment in the crate and will stand upright when the crate is placed on one of its six faces. What should the radius of the tank be if it is to be of the largest possible volume?
A. 4
B. 5
C. 6
D. 8
E. 10
A. 4
B. 5
C. 6
D. 8
E. 10
01 Sep 2010, 12:14
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aiming4mba
Volume of the cylinder equals to \(area=\pi{r^2}h\). First of all note that answer choices C, D, and E don't make sense. For example cylinder of a radius 6 (option C) just won't fit on any face, as max face has a dimensions 12*10 so cylinder with max radius of 5 can be placed on it.
Max volume will be when the base of a cylinder is placed on the face with dimension 12*10 thus the radius will be 5 --> \(v=\pi{5^2}*8=200\pi\);
Other options:
If we place cylinder on the face with dimension 12*8 then radius will be 4 and \(v=\pi{4^2}*10=160\pi\);
If we place cylinder on the face with dimension 10*8 then radius will be 4 and \(v=\pi{4^2}*12=192\pi\),.
Answer: B.
10 Sep 2014, 23:56
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IndianGuardian
The dimensions of the crate are 8*10*12. The rectangular base of the crate can be 8*10 or 10*12 or 8*12 and the height will be the leftover dimension.
To maximize volume of the cylinder, we must maximize radius and height. The diameter of the cylinder will be the measure of the shorter side of the base i.e. if the base of the crate measures 8*10, the diameter will be 8. So one thing is clear - the two sides of the crate should be as close as possible to each other in measure because some space gets wasted. Hence having the base as 8*12 and height as 10 doesn't make sense. It is much better to have base as 8*10 and height as 12 since diameter will be 8 in both cases but height will be 12 in the second case.
Now, radius gets squared so larger the radius, more impact it will have on volume as compared with height. But radius is half of diameter so some impact is lost. Let's review both leftover cases:
Base 8*10, height 12
Volume of cylinder \(= \pi*4^2*12 = 192*\pi\)
.
Base 10*12, height 8
Volume of cylinder \(= \pi*5^2*8 = 200*\pi\)
The volume will be maximum when base is 10*12 (so radius is 5).
Answer (B)
