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fmeinsen
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fmeinsen
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Nope, the answer is 1/8.
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Sumithra
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I get
Probability that three are heads = 5/16
Probability that first three are heads = 1/8
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trivikram
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5C3*(1/2)^3*(1/2)^2 = 5/16
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fmeinsen
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Hey trivikram

is there a difference between the folloing two questions?

1) Five coins are tossed one after the other. What is the probability that the first three are heads?

2) Five coins are tossed one after the other. What is the probability that overall three are heads?

Do both result in 5/16?

Thanks
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joeydvivre
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Of course there's a difference.

1) ANS = 1/8
2) ANS = 5C3 (1/32) = 10/32 = 5/16
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fmeinsen
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According to the GMAT Club Question collector the answer to question1 is
5C3*(1/2)^3*(1/2)^2 = 5/16
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trivikram
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joeydvivre
Of course there's a difference.

1) ANS = 1/8
2) ANS = 5C3 (1/32) = 10/32 = 5/16


I think this is correct...

the 1st one the event are independent of the total # of coins

but the latter one has a sample of 5 and we got to decide on that
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Yeah, but you can still be fooled on these.

For example -

1) I choose a card from a normal deck of cards, observe it is a heart, and then choose another card. What is the probability it is a club?

2) I choose two cards from a deck and throw them away. Then I choose a third card, what is the prob. it is a club?
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fmeinsen
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My solution would be:

1) Assume card is not being replaced & Assume that a card deck represents 52 cards: (52/4)/(52-1)

2) We do not know what type of cards the 1st two cards were..
a) assuming they were clubs: ((52/4)-2)/(52-2)
b) assuming they were not clubs: ((52/4))/(52-2)



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