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Flor is choosing three of five colors of paint to use for her art proj

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Flor is choosing three of five colors of paint to use for her art proj  [#permalink]

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New post 03 Apr 2018, 08:38
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Difficulty:

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Question Stats:

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Flor is choosing three of five colors of paint to use for her art project at school. Two of the colors, Green and Yellow, cannot both be selected. How many different ways can Flor choose the colors for her project?

A. 7
B. 9
C. 10
D. 13
E. 17

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Re: Flor is choosing three of five colors of paint to use for her art proj  [#permalink]

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New post 03 Apr 2018, 08:48
QZ wrote:
Flor is choosing three of five colors of paint to use for her art project at school. Two of the colors, Green and Yellow, cannot both be selected. How many different ways can Flor choose the colors for her project?

1. 7
2. 9
3. 10
4. 13
5. 17


Use \(Total - Restriction\) technique.

If she chooses Green and Yellow together then there will be three choices for the third color, so she can choose {Green, Yellow, Any of the remaining three} in 3 ways,

The total number of ways to choose 3 out of 5 is 5C3 = 10.

\(Total - Restriction=10-3=7\)

Answer: A.
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Re: Flor is choosing three of five colors of paint to use for her art proj  [#permalink]

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New post 05 Apr 2018, 16:11
1
QZ wrote:
Flor is choosing three of five colors of paint to use for her art project at school. Two of the colors, Green and Yellow, cannot both be selected. How many different ways can Flor choose the colors for her project?

A. 7
B. 9
C. 10
D. 13
E. 17


There are three cases: 1) green is one of the five colors chosen, but yellow isn’t, 2) yellow is one of the five colors chosen, but green isn’t, and 3) neither green nor yellow is chosen. Let’s analyze each case.

Case 1: Green is one of the five colors chosen, but yellow isn’t.

If green is chosen but yellow isn’t, then we have to choose 2 more colors from the 3 remaining colors. The number of ways to do that is 3C2 = 3.

Case 2: Yellow is one of the five colors chosen, but green isn’t.
This is analogous to case 1, so there are 3 ways for this case..

Case 3: Neither green nor yellow is chosen.

If neither color is chosen, then we have to choose 3 colors from the 3 remaining colors. The number of ways to do that is 3C3 = 1.

Thus, the total number of ways Flor can choose the colors for her project is 3 + 3 + 1 = 7.

Alternate Solution:

We can use the formula:

Total number of ways to pick 3 colors = number of ways where yellow and green are both included + number of ways where yellow and green are not both included

Since we are choosing 3 colors from 5 available colors, there are 5C3 = (5 x 4)/2 = 10 ways of doing this when there are no restrictions.

The number of ways where yellow and green are both included can be found easily by observing that yellow and green occupy two of the three slots; any one of the remaining three colors can occupy the final slot. So, there are 3 ways to choose colors where yellow and green are both included.

Thus, the number of ways to pick colors where yellow and green are not included together is 10 - 3 = 7.

Answer: A
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Re: Flor is choosing three of five colors of paint to use for her art proj  [#permalink]

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New post 05 Apr 2018, 17:26
# select colors without green and yellow = #selecting 3 colors out of 5 - # selecting 1 color in 3(assuming green and yellow are picked) = 5C3 - 3C1

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Re: Flor is choosing three of five colors of paint to use for her art proj  [#permalink]

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New post 12 Sep 2018, 06:15
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AkshdeepS wrote:
Flor is choosing three of five colors of paint to use for her art project at school. Two of the colors, Green and Yellow, cannot both be selected. How many different ways can Flor choose the colors for her project?

A. 7
B. 9
C. 10
D. 13
E. 17


The posters above me have demonstrated the approach that I'd typically use.
However, it's important to note that, when the answer choices are so small (as they are here), we should also consider the straightforward strategy of listing and counting

Let R, B, P, G and Y represent the colors Red, Blue, Purple, Green and Yellow respectively.

Now let's list the possible outcomes that meet all of the given conditions:
- RBP
- RBG
- RBY
- RPG
- RPY
- BPG
- BPY
Done!! So, there are 7 possible outcomes

Answer: A

Cheers,
Brent
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Re: Flor is choosing three of five colors of paint to use for her art proj  [#permalink]

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New post 16 Sep 2018, 12:00
AkshdeepS wrote:
Flor is choosing three of five colors of paint to use for her art project at school. Two of the colors, Green and Yellow, cannot both be selected. How many different ways can Flor choose the colors for her project?

A. 7
B. 9
C. 10
D. 13
E. 17

RENAME colors to "unblock your brain": A, B, C, D and E.

Restriction: A and B cannot be BOTH chosen.

? = Number of choices of 3 colors among the 5 given, restriction obeyed.


First Scenario: neither A nor B is chosen.
There is just one possibility : CDE

Second Scenario: A is chosen (hence B is not)
There is just three possibilities: ACD, ACE, ADE.

Third Scenario: B is chosen (hence A is not)
This is similar to the previous scenario, hence additional 3 cases.

All cases mentioned above are MUTUALLY EXCLUSIVE, therefore they may be added: 7 possibilities.

All 7 cases are EXHAUSTIVE, hence we are sure the answer is (at least 7 and) not greater than 7.


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: Flor is choosing three of five colors of paint to use for her art proj &nbs [#permalink] 16 Sep 2018, 12:00
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