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rbcola
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For 3 Venn diag we have A +B+C- + ABC Qstem = AB=16, BC=18, Updated on: 29 Jun 2008, 07:47
Originally posted by rbcola on 16 Aug 2006, 15:05.
Last edited by rbcola on 29 Jun 2008, 07:47, edited 2 times in total.
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For 3 Venn diag we have
A +B+C-[AB+BC+AC] + ABC
Qstem = AB=16, BC=18, AC=17



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For 3 Venn diag we have A +B+C- + ABC Qstem = AB=16, BC=18, 16 Aug 2006, 17:15
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rbcola
Set A, B, C have some elements in common. if 16 elements are in both A and B, 17 elements are in both A and C, and 18 elements are in both B and C, how many elements do all three of the sets A, B, and C have in common?

1). of the 16 elements that are in both A and B, 9 elements are also in C
2). A has 25 elements, B has 30 elements, and C has 35 elements.
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its A.
from i, abc = 9.
from ii, abc could be 8 or 9.
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For 3 Venn diag we have A +B+C- + ABC Qstem = AB=16, BC=18, 16 Aug 2006, 18:53
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Professor .. How do you get ABC = 8 or 9 in ii, please elaborate. OA is A
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For 3 Venn diag we have A +B+C- + ABC Qstem = AB=16, BC=18, 16 Aug 2006, 21:18
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A

AB = 17

St1: ABC = 9 : SUFF

St2: Let x = Only A and y = ABC
Then x = 25-16-18+y
so x = y-9
max value of y could be 16. So ABC could vary from 9 to 16.: INSUFF
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For 3 Venn diag we have A +B+C- + ABC Qstem = AB=16, BC=18, 17 Aug 2006, 21:29
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rbcola
Set A, B, C have some elements in common. if 16 elements are in both A and B, 17 elements are in both A and C, and 18 elements are in both B and C, how many elements do all three of the sets A, B, and C have in common?

1). of the 16 elements that are in both A and B, 9 elements are also in C

2). A has 25 elements, B has 30 elements, and C has 35 elements.

Can anybody help out this one. Thanks
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For 3 Venn diag we have
A +B+C-[AB+BC+AC] + ABC
Qstem = AB=16, BC=18, AC=17

(2) We know A, B,C We can find ABC

BD

(1)Not Suff

B
Heman

(1)
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For 3 Venn diag we have A +B+C- + ABC Qstem = AB=16, BC=18, 17 Aug 2006, 21:48
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[quote="heman]
For 3 Venn diag we have
A +B+C-[AB+BC+AC] + ABC
Qstem = AB=16, BC=18, AC=17
[/quote]

Shouldn't this be AUBUC = A+B+C-(AB+BC+CA) - 2ABC please?
But, agreed, stmt (2) also let's us find out ABC. Hence answer should be (D).
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For 3 Venn diag we have A +B+C- + ABC Qstem = AB=16, BC=18, 18 Aug 2006, 00:31
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prashrash


Shouldn't this be AUBUC = A+B+C-(AB+BC+CA) - 2ABC please?
But, agreed, stmt (2) also let's us find out ABC. Hence answer should be (D).
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AUBUC is A + B + C - (AB + BC + CA) + ABC

AB, BC and CA also include elements that are common to all 3.
For instance, if an element figures in all sets A, B and C it will definitely figure in AB, in BC and in CA.

Therefore, if it is subtracted thrice, one has to add it back once.



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