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For all numbers m and n, m◊n = m^2(m - n)/n^2. What is the value of 3◊

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For all numbers m and n, m◊n = m^2(m - n)/n^2. What is the value of 3◊  [#permalink]

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New post 05 Mar 2019, 02:47
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For all numbers m and n, \(m◊n = \frac{m^2(m - n)}{n^2}\). What is the value of 3◊2 ?


A. 1/2

B. 9/4

C. 3/2

D. 3

E. 9
Spoiler: OA

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Re: For all numbers m and n, m◊n = m^2(m - n)/n^2. What is the value of 3◊  [#permalink]

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New post 05 Mar 2019, 03:05
Bunuel wrote:
For all numbers m and n, \(m◊n = \frac{m^2(m - n)}{n^2}\). What is the value of 3◊2 ?


A. 1/2

B. 9/4

C. 3/2

D. 3

E. 9



Given,

\(m◊n = \frac{m^2(m - n)}{n^2}\)

\(3◊2 = \frac{3^2(3 - 2)}{2^2}\)

\(3◊2 = \frac{9*1}{4}\)

\(3◊2 = \frac{9}{4}\)

B is the correct answer.
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Re: For all numbers m and n, m◊n = m^2(m - n)/n^2. What is the value of 3◊  [#permalink]

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New post 05 Mar 2019, 09:10
Bunuel wrote:
For all numbers m and n, \(m◊n = \frac{m^2(m - n)}{n^2}\). What is the value of 3◊2 ?


A. 1/2

B. 9/4

C. 3/2

D. 3

E. 9


substitute m=3 and n=2
\(m◊n = \frac{m^2(m - n)}{n^2}\)
we get
9/4
IMO B
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Re: For all numbers m and n, m◊n = m^2(m - n)/n^2. What is the value of 3◊  [#permalink]

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New post 07 Mar 2019, 07:59
Bunuel wrote:
For all numbers m and n, \(m◊n = \frac{m^2(m - n)}{n^2}\). What is the value of 3◊2 ?


A. 1/2

B. 9/4

C. 3/2

D. 3

E. 9


Letting m = 3 and n = 2, we have:

3^2(3 - 2)/2^2 = 9/4

Answer: B
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Re: For all numbers m and n, m◊n = m^2(m - n)/n^2. What is the value of 3◊   [#permalink] 07 Mar 2019, 07:59
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