It is currently 21 Oct 2017, 18:50

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# For any positive integer n, the sum of the first n positive

Author Message
Manager
Joined: 06 Nov 2008
Posts: 53

Kudos [?]: 6 [0], given: 0

For any positive integer n, the sum of the first n positive [#permalink]

### Show Tags

11 Dec 2008, 18:13
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

For any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2. What is the sum of all the even integers between 99 and 301?

A. 10,100
B. 20,200
C. 22,650
D. 40,200
E. 45,150

Kudos [?]: 6 [0], given: 0

SVP
Joined: 29 Aug 2007
Posts: 2472

Kudos [?]: 843 [1], given: 19

### Show Tags

11 Dec 2008, 18:27
1
KUDOS
haichao wrote:
For any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2. What is the sum of all the even integers between 99 and 301?

A. 10,100
B. 20,200
C. 22,650
D. 40,200
E. 45,150

Last even integer = 300
First even integer = 100
no. of even integers between 99 and 301 = (300/2 - 100/2) + 1 = 101

sum = no of even integers x average of even integers
sum = 101 (100+300)/2
sum = 101 (200)
sum = 20200
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Kudos [?]: 843 [1], given: 19

Manager
Joined: 27 May 2008
Posts: 200

Kudos [?]: 45 [0], given: 0

### Show Tags

11 Dec 2008, 20:58
GMAT TIGER cool explanation kudos to you +1

Kudos [?]: 45 [0], given: 0

Re: sum   [#permalink] 11 Dec 2008, 20:58
Display posts from previous: Sort by