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23 Jul 2013, 15:19
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For any positive x, y and k, if kx is n% of y, then what percentage must x be of y?
A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
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23 Jul 2013, 15:24
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Revenge2013
For any positive x, y and k, if kx is n% of y, then what percentage must x be of y?
A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
GIVENA) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
\(KX = (N/100)*Y\)
We have to find \((X/Y)*100\)
\(KX = (N/100)*Y\) ==> CLEARLY \((X/Y)*100 = N/K\) ...HENCE A
23 Jul 2013, 15:27
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Revenge2013
For any positive x, y and k, if kx is n% of y, then what percentage must x be of y?
A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
kx is n% of y --> \(kx=y*\frac{n}{100}\) --> \(\frac{100x}{y}=\frac{n}{y}\).
What percentage must x be of y --> \(x=y*\frac{?}{100}\) --> \(?=\frac{100x}{y}\) --> \(?=\frac{n}{y}\).
Answer: A.
