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# For dinner at a restaurant, there are x choices of appetizers, y + 1

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Joined: 02 Sep 2009
Posts: 64216
For dinner at a restaurant, there are x choices of appetizers, y + 1  [#permalink]

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09 Jun 2016, 02:46
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Difficulty:

5% (low)

Question Stats:

81% (01:07) correct 19% (01:30) wrong based on 158 sessions

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For dinner at a restaurant, there are x choices of appetizers, y + 1 main courses, and z choices of dessert. How many total possible choices are there if you choose 1 appetizer, 1 main course, and 1 dessert for your meal?

A. x + y + z + 1
B. xyz + xz
C. xy + z + 1
D. xyz + 1
E. xyz + 1/2

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Re: For dinner at a restaurant, there are x choices of appetizers, y + 1  [#permalink]

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09 Jun 2016, 03:03
1
1
Bunuel wrote:
For dinner at a restaurant, there are x choices of appetizers, y + 1 main courses, and z choices of dessert. How many total possible choices are there if you choose 1 appetizer, 1 main course, and 1 dessert for your meal?

A. x + y + z + 1
B. xyz + xz
C. xy + z + 1
D. xyz + 1
E. xyz + 1/2

x appetizers,
y + 1 main courses,
z dessert

Required: 1 appetizer, 1 main course, and 1 dessert
Number of ways possible = xC1*(y+1)C1*zC1 {NC1 = N! / (N-1)!*1! = N}

Hence, number of ways = x(y+1)z = xyz + xz

Correct Option: B
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Re: For dinner at a restaurant, there are x choices of appetizers, y + 1  [#permalink]

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09 Jun 2016, 03:22
We have to choose 1 appetizer, 1 main course, and 1 dessert for the meal out of x choices of appetizers, y + 1 main courses, and z choices of dessert.

This can be done in xC1 . (y+1)C1 . zC1 ways = x(y+1)z = xyz + xz (Option B).
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Re: For dinner at a restaurant, there are x choices of appetizers, y + 1  [#permalink]

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09 Jun 2016, 08:07
Bunuel wrote:
For dinner at a restaurant, there are x choices of appetizers, y + 1 main courses, and z choices of dessert. How many total possible choices are there if you choose 1 appetizer, 1 main course, and 1 dessert for your meal?

A. x + y + z + 1
B. xyz + xz
C. xy + z + 1
D. xyz + 1
E. xyz + 1/2

Possible ways to choose 1 appetizer out of x= x
Possible ways to choose 1 main course out of y+1= y+1
Possible ways to choose 1 dessert out of z= z

So possible ways to choose 1 appetizer, 1 main course, and 1 dessert:-

x (y+1) (z) = xyz+xz

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Re: For dinner at a restaurant, there are x choices of appetizers, y + 1  [#permalink]

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15 Mar 2020, 04:08
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: For dinner at a restaurant, there are x choices of appetizers, y + 1   [#permalink] 15 Mar 2020, 04:08