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For each month of next year, Company R's monthly revenue

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For each month of next year, Company R's monthly revenue  [#permalink]

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New post 07 Dec 2007, 09:38
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For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month. What is Company R's revenue target for March of next year?

(1) Company R's revenue target for December of next year is $310,000

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year.
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Re: For each month of next year, Company R's monthly revenue  [#permalink]

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New post 07 Dec 2007, 10:05
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Answer is C

1. We know the target for December is $310,000. We know March is 9 months earlier, but we don't know x.

2. We know X is $10,000 but have no starting point to find March with.

combined we know $310,000 is December
Nov: $300,000
Oct: $290,000
Sep: $280,000
Aug: $270,000
July: $260,000
June: $250,000
May: $240,000
April: $230,000
March: $220,000

or you could just take $310,000 - ($10,000 * 9 months) = $220,000
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Re: For each month of next year, Company R's monthly revenue  [#permalink]

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New post 07 Dec 2007, 10:11
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1
J=target revenue for January

Stmt 1. J+11x=310,000

Two variables, insuff

Stmt 2. J+9x=J+5x +30,000

Two variables, insuff

Together we have two equations with two variables. Suff

Ans C.
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Re: For each month of next year, Company R's monthly revenue  [#permalink]

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New post 29 Aug 2011, 14:08
eschn3am wrote:
Answer is C

1. We know the target for December is $310,000. We know March is 9 months earlier, but we don't know x.

2. We know X is $10,000 but have no starting point to find March with.

combined we know $310,000 is December
Nov: $300,000
Oct: $290,000
Sep: $280,000
Aug: $270,000
July: $260,000
June: $250,000
May: $240,000
April: $230,000
March: $220,000

or you could just take $310,000 - ($10,000 * 9 months) = $220,000


Please help me understand how did we calculate x=10,000 from statement 2.
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Re: For each month of next year, Company R's monthly revenue  [#permalink]

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New post 29 Aug 2011, 14:28
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DeeptiM wrote:
eschn3am wrote:
Answer is C

1. We know the target for December is $310,000. We know March is 9 months earlier, but we don't know x.

2. We know X is $10,000 but have no starting point to find March with.

combined we know $310,000 is December
Nov: $300,000
Oct: $290,000
Sep: $280,000
Aug: $270,000
July: $260,000
June: $250,000
May: $240,000
April: $230,000
March: $220,000

or you could just take $310,000 - ($10,000 * 9 months) = $220,000


Please help me understand how did we calculate x=10,000 from statement 2.


It is an arithmetic progression:

Let R be the revenue target for June.
For July; revenue target=R+x
For August; revenue target=R+2x
For September; revenue target=R+3x

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of mext year.

\(R+3x-R=30000\)
\(x=10000\)-------------------------1
Not Sufficient.

(1) Company R's revenue target for December of next year is $310,000

Let Jan's revenue target be J,

Common difference is "x". First term(January)=J; Last term or 12th term, say D(December)

\(A_n=A_1+(n-1)d\)

\(D=J+(n-1)x\)
\(D=J+(12-1)x\)

\(310000=J+11x\)-----2
Not Sufficient.

Using 1 and 2, we get J and we know x.

March Revenue Target= J+2x
Sufficient.

Ans: "C"
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Re: For each month of next year, Company R's monthly revenue  [#permalink]

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New post 29 Aug 2011, 16:52
2
JAN FEB MAR APR MAY......... .DEC
a a+x a+2x a+11x


a+2x=?

1. Not Sufficient
a+11x = 310000

we dont know a or x. In other words different a , will give different x.

2. Not sufficient

a+8x = 30000 + a+5x

x can be found . But no info on a.

Together,

a+11x = 310000 and we have x from 2.

Hence this is Sufficient.

Answer is C.
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Re: For each month of next year, Company R's monthly revenue  [#permalink]

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New post 05 Feb 2016, 09:55
J (January), J + X, J +2X = ?
1) J + 11X = 310,000 Not sufficient.
2) J + 8X = J + 5X + 30,000 ; 3X = 30,000 ; X = 10,000
But do not know J, not sufficient
1) & 2) J + 11*10,000 = 310,000 ; J = 200,000 Done
Answer C.
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Re: For each month of next year, Company R's monthly revenue  [#permalink]

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New post 18 Feb 2016, 11:55
Thanks for sharing the solution.
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Re: For each month of next year, Company R's monthly revenue  [#permalink]

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New post 06 Jun 2016, 21:05
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Given: Monthly revenue target is x dollars greater than the target for the previous month
Required: Revenue for March of next year

Statement 1: Target for Dec = 310,000
Target for January = 310,000 + x
Target for February = 310,000 + 2x
Target for March = 310,000 = 3x

But we have no clue about x
INSUFFICIENT

Statement 2: Revenue for September - Revenue for June = 30,000
Hence 3x = 30,000
But we have no idea about the actual revenues.
INSUFFICIENT

Combining both statements:
We know the value of x and we know the value in one of the months,
Hence we can calculate the revenue in March
SUFFICIENT

Correct Option: C
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Re: For each month of next year, Company R's monthly revenue  [#permalink]

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New post 03 Aug 2017, 06:17
OptimusPrepJanielle wrote:
Given: Monthly revenue target is x dollars greater than the target for the previous month
Required: Revenue for March of next year

Statement 1: Target for Dec = 310,000
Target for January = 310,000 + x
Target for February = 310,000 + 2x
Target for March = 310,000 = 3x

But we have no clue about x
INSUFFICIENT

Statement 2: Revenue for September - Revenue for June = 30,000
Hence 3x = 30,000
But we have no idea about the actual revenues.
INSUFFICIENT

Combining both statements:
We know the value of x and we know the value in one of the months,
Hence we can calculate the revenue in March
SUFFICIENT

Correct Option: C


Hi,

I am not able to follow why x=10,000? Can someone explain this
Re: For each month of next year, Company R's monthly revenue &nbs [#permalink] 03 Aug 2017, 06:17
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