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1. The problem asks us to find the year-end price of 100 grams of gold for a certain year. The best way to do this is to calculate the price for each of the given years and see which one is closest to the answer.

2. 100 grams can be converted to \(\frac{100}{31.1}\) troy ounces.

3. We are given the years 2005, 2008, and 2010. Looking at the graph, we get the following prices, which we can fill in a table:

YearsPrice for 1 troy ounce of goldPrice for \(\frac{100}{31.1}\) troy ounces of goldEstimated year-end price
2005300£??
2008600£??
2010900£??

4. To get the price for \(\frac{100}{31.1}\) troy ounces of gold, we need just need to multiply by \(\frac{100}{31.1}\).

YearsPrice for 1 troy ounce of goldPrice for \(\frac{100}{31.1}\) troy ounces of goldEstimated year-end price
2005300£\(\approx\)964.23£960£
2008600£\(\approx\)1929.26£1930£
2010900£\(\approx\)2893.89£2900£


5. Our answer options are: 300, 600, 1200, 1900, and 2500. The closest price to one of the options is from the year 2008. So, our answer will be 2008 and 1900.
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For easier alculation take multiply the proce by 3 as this will be the proce foe 31 x 3 grams : 93 grams and the right proce will be a bit highr than that.
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