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14 Oct 2020, 00:15
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
89% (01:21) correct
11%
(02:19)
wrong
based on 199
sessions
History
Date
Time
Result
Not Attempted Yet
\((\sqrt[3]{64}+\sqrt[3]{x})^2=36\)
For the equation shown above, what could be the value of x ?
A. 6
B. 7
C. 8
D. 12
E. 14
For the equation shown above, what could be the value of x ?
A. 6
B. 7
C. 8
D. 12
E. 14
14 Oct 2020, 02:55
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Explanation:
\((\sqrt[3]{64}+\sqrt[3]{x})^2=36\)
\((4 +\sqrt[3]{x})^2 = 6^2\)
Square root both side:
\((\sqrt[3]{x}) =6-4\)
\((\sqrt[3]{x}) =2\)
Cube both side.
x=2^3
x=8
IMO-C
\((\sqrt[3]{64}+\sqrt[3]{x})^2=36\)
\((4 +\sqrt[3]{x})^2 = 6^2\)
Square root both side:
\((\sqrt[3]{x}) =6-4\)
\((\sqrt[3]{x}) =2\)
Cube both side.
x=2^3
x=8
IMO-C
14 Oct 2020, 04:19
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Quote:
Step 1: Understanding the question
\(\sqrt[3]{64}\) = 4
\((4 + \sqrt[3]x)^2\) = 36
4 + \(\sqrt[3]x\) = ±6
As sum of 4 and \(\sqrt[3]x\) is an integer, \(\sqrt[3]x\) is integer
As per options only when x = 8, \(\sqrt[3]x\) = \(\sqrt[3]8\) = 2
IMO C
