If two numbers ‘a’ and ‘b’ are reciprocals, \(\frac{a = 1}{b}\) and vice versa.
Therefore, if \(\frac{6+4√n }{ n}\) and \(\frac{6-4√n }{ n}\) are reciprocals,
\(\frac{6 + 4√n }{ n}\) = \(\frac{n }{ 6 - 4√n}\).
Cross multiplying, we have,
(6 + 4√n) (6-4√n) =\( n^2\).
Using the algebraic identity (a+b)(a-b) = \(a^2\) –\( b^2\), we have,
\(6^2\) – \((4√n)^2\) = \(n^2\). Simplifying, we have,
36 – 16n = \(n^2\) OR
\(n^2\) + 16 n = 36.
Instead of trying to solve this equation, why don’t we plug in values from the answer options?
Answer option A says n= 1.
\(1^2\) + 16 * 1 ≠ 36. Answer option A can be ruled out.
Answer options C, D and E can be ruled out because if n = 6 or n = 8, the LHS will become greater than 36.
Answer option B, which is left out, HAS TO be the correct answer option.
If n = 2, \(2^2\) + 16 * 2 = 4 + 32 = 36.
The correct answer option is B.
Hope that helps!