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Hi.
the conditions of n :
1. n cannot be 0.
in 6+4√n/n , since n is the only denominator term. Something divided by zero is undefined .
2. n cannot be negative .
otherwise, √n would be imaginary number. (√-1=i)

therefore, we can conclude n is a positive number.
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If two numbers ‘a’ and ‘b’ are reciprocals, \(\frac{a = 1}{b}\) and vice versa.

Therefore, if \(\frac{6+4√n }{ n}\) and \(\frac{6-4√n }{ n}\) are reciprocals,

\(\frac{6 + 4√n }{ n}\) = \(\frac{n }{ 6 - 4√n}\).

Cross multiplying, we have,
(6 + 4√n) (6-4√n) =\( n^2\).

Using the algebraic identity (a+b)(a-b) = \(a^2\) –\( b^2\), we have,

\(6^2\) – \((4√n)^2\) = \(n^2\). Simplifying, we have,

36 – 16n = \(n^2\) OR

\(n^2\) + 16 n = 36.

Instead of trying to solve this equation, why don’t we plug in values from the answer options?

Answer option A says n= 1.
\(1^2\) + 16 * 1 ≠ 36. Answer option A can be ruled out.

Answer options C, D and E can be ruled out because if n = 6 or n = 8, the LHS will become greater than 36.

Answer option B, which is left out, HAS TO be the correct answer option.
If n = 2, \(2^2\) + 16 * 2 = 4 + 32 = 36.

The correct answer option is B.

Hope that helps!
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For (6+4√n)/n and (6−4√n)/n to be reciprocals,
=> ((6+4√n)/n)x((6−4√n)/n) = 1
=> ((36-16n)/n^2)=1
=> n^2+16n-36=0

Now , check from options
(A) 1, not satisfies
(B) 2, satisfies
(C) 4, [color=#ff0000]not satisfies
(D) 6, not satisfies
(E) 8, not satisfies[/color]

Hence B
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