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Bunuel
For which of the following values of c will there be only 1 distinct real solution to the equation 3x^2 + 8x + c = 0 ?

(A) 0
(B) 4 3/3
(C) 3 1/8
(D) 4 1/2
(E) 5 1/3
There is one real root whwn \(b^2 −4ac = 0\)

Thus, \(64 - 12c =0 \)

Or, \(c = \frac{64}{12} = \frac{16}{3} = 5 \frac{1}{3}\), Answer must be (E)
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There is one real root when
[ltr]b2−4ac=0[/ltr]


Thus,
[ltr]64−12c=0[/ltr]


Or,
[ltr]c=64/12=16/3=5(1/3)[/ltr]


Bunuel
For which of the following values of c will there be only 1 distinct real solution to the equation 3x^2 + 8x + c = 0 ?

(A) 0
(B) 4 3/3
(C) 3 1/8
(D) 4 1/2
(E) 5 1/3
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