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Forty percent of the residents of Town T are men, and 15 percent of th

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Forty percent of the residents of Town T are men, and 15 percent of th  [#permalink]

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New post 05 Aug 2018, 00:40
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Forty percent of the residents of Town T are men, and 15 percent of those men are over the age of 60. If one resident of the town is to be selected at random,
what is the probability that the resident selected is a man over the age of 60?

(A) 0.02
(B) 0.06
(C) 0.11
(D) 0.20
(E) 0.55
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Forty percent of the residents of Town T are men, and 15 percent of th  [#permalink]

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New post 05 Aug 2018, 01:28
Bismarck wrote:
Forty percent of the residents of Town T are men, and 15 percent of those men are over the age of 60. If one resident of the town is to be selected at random,
what is the probability that the resident selected is a man over the age of 60?

(A) 0.02
(B) 0.06
(C) 0.11
(D) 0.20
(E) 0.55


Let 'n' be the total nos. of residents in the town.
Given, number of men residents=40% of n=0.4n
Given, number of men residents over the age 60=15% of number of men residents=0.15*0.4n=0.06n

P(resident selected is a man over 60 age)=\(\frac{Number-of-men-residents-over the age-60}{Total-nos.-of-residents-in-the-town}\)=\(\frac{0.06n}{n}\)=0.06

Ans. (B)
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Forty percent of the residents of Town T are men, and 15 percent of th  [#permalink]

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New post 05 Aug 2018, 07:59
Bismarck wrote:
Forty percent of the residents of Town T are men, and 15 percent of those men are over the age of 60. If one resident of the town is to be selected at random,
what is the probability that the resident selected is a man over the age of 60?

(A) 0.02
(B) 0.06
(C) 0.11
(D) 0.20
(E) 0.55

Let # of residents of town T = 100

(1) # of men? 40% of 100 residents are men
-- There are 40 men

(2) # of men in T who are over age 60? 15 percent of "those" [40] men are over age 60:
\(.15(40)=6\)
There are 6 men in Town T over age 60

(3) Probability? Probability that a random resident is a man [and] over the age of 60?
Favorable = \(6\) (man and over 60)
Possible = \(100\) (residents)
\(P=\frac{Favorable}{Possible}=\frac{6}{100}=0.06\)

Answer B
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Re: Forty percent of the residents of Town T are men, and 15 percent of th  [#permalink]

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New post 05 Aug 2018, 09:01
Bismarck wrote:
Forty percent of the residents of Town T are men, and 15 percent of those men are over the age of 60. If one resident of the town is to be selected at random,
what is the probability that the resident selected is a man over the age of 60?

Favorable outcome = 0.40 * 0.15 * n = 0.06 * n
Possible outcome = n

Probability = Favorable outcome / Possible outcome = 0.06 * n / n = 0.06

Hence, B.
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Re: Forty percent of the residents of Town T are men, and 15 percent of th  [#permalink]

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New post 05 Aug 2018, 09:12
6 men above 60.
So probable/ total = 6/100 = 0.06

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Re: Forty percent of the residents of Town T are men, and 15 percent of th &nbs [#permalink] 05 Aug 2018, 09:12
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