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Four brothers split a sum of money between them. The first brother rec

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Four brothers split a sum of money between them. The first brother rec  [#permalink]

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New post 13 Mar 2020, 03:53
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Four brothers split a sum of money between them. The first brother received 50% of the total, the second received 25% of the total, the third received 20% of the total, and the fourth received the remaining $4. The first brother received how much more money than the third brother received?

(A) $4
(B) $16
(C) $20
(D) $24
(E) $36

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Four brothers split a sum of money between them. The first brother rec  [#permalink]

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New post 13 Mar 2020, 08:36
GIVEN DATA

1st bro 50%
2nd bro 25%
3rd bro 20%

4th bro gets the remaining money, which are $4.

Money(1st bro)-money(3rd bro)=?


SOLUTION

4th bro gets the remaining= 100%-50%-25%-20%=5%, which is equivalent to $4 (given)

So
- 1st bro gets $4*10=$40
- 3rd bro gets $4*4=$16

Money(1st bro)-money(3rd bro)=40-16=24

D is te correct answer
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Re: Four brothers split a sum of money between them. The first brother rec  [#permalink]

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New post 13 Mar 2020, 08:52
Bunuel wrote:
Four brothers split a sum of money between them. The first brother received 50% of the total, the second received 25% of the total, the third received 20% of the total, and the fourth received the remaining $4. The first brother received how much more money than the third brother received?

(A) $4
(B) $16
(C) $20
(D) $24
(E) $36


% of money received by the 4 th son is 100 - ( 50 + 25 + 20 ) = 5%

Now, 5% represents $ 4

So, first brother received ( 50 - 20 = 30%) more money than the third brother received

Thus, Answer must be 4*6 = $24 , Answer must be (D)
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Re: Four brothers split a sum of money between them. The first brother rec  [#permalink]

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New post 15 Mar 2020, 02:38
Bunuel wrote:
Four brothers split a sum of money between them. The first brother received 50% of the total, the second received 25% of the total, the third received 20% of the total, and the fourth received the remaining $4. The first brother received how much more money than the third brother received?

(A) $4
(B) $16
(C) $20
(D) $24
(E) $36


from given info
x/2+x/4+x/5+4 = x
solve for x = 80
so first brother received 40 $ and third received $16
40-16 ; 24 $
IMO D
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Re: Four brothers split a sum of money between them. The first brother rec  [#permalink]

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New post 03 May 2020, 04:37
Bunuel wrote:
Four brothers split a sum of money between them. The first brother received 50% of the total, the second received 25% of the total, the third received 20% of the total, and the fourth received the remaining $4. The first brother received how much more money than the third brother received?

(A) $4
(B) $16
(C) $20
(D) $24
(E) $36


We see that the fourth brother receives 5% of the total money. Since he received $4 and the third brother received 20% or 4 times his percent share, the third brother received 4 times as much money also, or $16. Similarly, the first brother received 50%, or 10 times, the fourth brother’s percent share, the first brother received 10 times as much money, or $40. Therefore, the first brother received 40 - 16 = $24 more than the third brother received.

Answer: D


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Re: Four brothers split a sum of money between them. The first brother rec   [#permalink] 03 May 2020, 04:37

Four brothers split a sum of money between them. The first brother rec

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