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13 Mar 2020, 04:53
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
86% (01:30) correct
14%
(01:22)
wrong
based on 132
sessions
History
Date
Time
Result
Not Attempted Yet
Four brothers split a sum of money between them. The first brother received 50% of the total, the second received 25% of the total, the third received 20% of the total, and the fourth received the remaining $4. The first brother received how much more money than the third brother received?
(A) $4
(B) $16
(C) $20
(D) $24
(E) $36
(A) $4
(B) $16
(C) $20
(D) $24
(E) $36
13 Mar 2020, 09:36
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GIVEN DATA
1st bro 50%
2nd bro 25%
3rd bro 20%
4th bro gets the remaining money, which are $4.
Money(1st bro)-money(3rd bro)=?
SOLUTION
4th bro gets the remaining= 100%-50%-25%-20%=5%, which is equivalent to $4 (given)
So
- 1st bro gets $4*10=$40
- 3rd bro gets $4*4=$16
Money(1st bro)-money(3rd bro)=40-16=24
D is te correct answer
1st bro 50%
2nd bro 25%
3rd bro 20%
4th bro gets the remaining money, which are $4.
Money(1st bro)-money(3rd bro)=?
SOLUTION
4th bro gets the remaining= 100%-50%-25%-20%=5%, which is equivalent to $4 (given)
So
- 1st bro gets $4*10=$40
- 3rd bro gets $4*4=$16
Money(1st bro)-money(3rd bro)=40-16=24
D is te correct answer
13 Mar 2020, 09:52
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Bunuel
% of money received by the 4 th son is 100 - ( 50 + 25 + 20 ) = 5%
Now, 5% represents $ 4
So, first brother received ( 50 - 20 = 30%) more money than the third brother received
Thus, Answer must be 4*6 = $24 , Answer must be (D)
