dave13 wrote:

hello

let bus one be x

let bus two be y

third bus = z

x= 1.40 %

y = 100 %

z= 1.30 %

Fourh bus = 2y --> 200

140+100+130+200/4 = 142.5

mode is number that occurs most ... frm this set of numbers i dont see such number... all numbers are unique 140+100+130+200

so what did i do wrong ?

Well Dave,

If you see all values are rotating around the Second Bus and the other three buses are expressed in percentage terms of the second bus.

So we assume the number of tourists in the Second Bus = 100

That makes the number of tourists in the First Bus = 140

It also makes the number of tourists in the Third Bus = 200

Fourth Bus has double passengers of that of Second. So it will be 200 in Fourth Bus as well.

Total Passengers = 100 + 140 + 200 + 200 = 640

Arithmetic Mean = 640/4 = 160

Mode of (100,140,200,200) is = 200

So the Mean is nothing but 80% of the Mode.

Hence Option E = 80 is the OA

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