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Fred and Sam are standing 45 miles apart and they start walking in a

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Fred and Sam are standing 45 miles apart and they start walking in a  [#permalink]

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New post 03 Jan 2016, 12:44
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Fred and Sam are standing 45 miles apart and they start walking in a straight line toward each other at the same time. If Fred walks at a constant speed of 4 miles per hour and Sam walks at a constant speed of 5 miles per hour, how many miles has Sam walked when they meet?

A. 5
B. 9
C. 25
D. 30
E. 45

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Re: Fred and Sam are standing 45 miles apart and they start walking in a  [#permalink]

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New post 06 Jan 2016, 02:55
relative distance =45 miles
relative speed =4+5 =9 miles per hour
time taken =45/9=5 hours
distance travelled by sam =5*5=25 miles
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Fred and Sam are standing 45 miles apart and they start walking in a  [#permalink]

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New post 07 Jan 2016, 02:21
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Bunuel wrote:
Fred and Sam are standing 45 miles apart and they start walking in a straight line toward each other at the same time. If Fred walks at a constant speed of 4 miles per hour and Sam walks at a constant speed of 5 miles per hour, how many miles has Sam walked when they meet?

A. 5
B. 9
C. 25
D. 30
E. 45


This question tests your knowledge about relative speeds and distance.
If two persons/vehicles are moving in the opposite direction, then the distance will reduce at a rate of (Speed of 1 + Sped of 2)
If two the persons/vehicles are moving in the same direction, then the distance will reduce at a rate of (Speed of 1 - Sped of 2)


Attachment:
fred sam distance.JPG
fred sam distance.JPG [ 11.6 KiB | Viewed 2251 times ]


Since Fred and Sam are moving in the opposite direction, hence distance will reduce in the rate of (Speed of Fred + Speed of Sam)
Time after which they meet = 45/(4 + 5) = 5 hours.

Hence miles walked by Sam in 5 hours = 5*5 = 25 miles.
Option C
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Re: Fred and Sam are standing 45 miles apart and they start walking in a  [#permalink]

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New post 07 Jan 2016, 15:50
are these really 600-700 lvl questions---because im getting them right :roll:
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Re: Fred and Sam are standing 45 miles apart and they start walking in a  [#permalink]

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New post 07 Jan 2016, 21:51
For more on relative speed, check out:
http://www.veritasprep.com/blog/2012/07 ... elatively/
http://www.veritasprep.com/blog/2012/08 ... -concepts/
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Re: Fred and Sam are standing 45 miles apart and they start walking in a  [#permalink]

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New post 24 Feb 2019, 06:47
Bunuel wrote:
Fred and Sam are standing 45 miles apart and they start walking in a straight line toward each other at the same time. If Fred walks at a constant speed of 4 miles per hour and Sam walks at a constant speed of 5 miles per hour, how many miles has Sam walked when they meet?

A. 5
B. 9
C. 25
D. 30
E. 45


Let t denote the time (in hours) until they meet. We can create the equation:

4t + 5t = 45

9t = 45

t = 5 hours

Thus, Sam has walked 5 x 5 = 25 miles when they meet.

Answer: C
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Re: Fred and Sam are standing 45 miles apart and they start walking in a   [#permalink] 24 Feb 2019, 06:47
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