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rxs0005
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From 6 men and 4 women a committee of 5 is to be formed. In 12 Jan 2005, 17:08
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From 6 men and 4 women a committee of 5 is to be formed. In how many ways this can be done if the committee is to include at least one woman.



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From 6 men and 4 women a committee of 5 is to be formed. In 12 Jan 2005, 20:53
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is it 255? or am I reading the question wrong..
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From 6 men and 4 women a committee of 5 is to be formed. In 12 Jan 2005, 21:27
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Total Number of ways to select 5 ppl - Total ways to select committee of 5 men or no women

10C5 - 6C5 = 252 - 6 = 246 ways.
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From 6 men and 4 women a committee of 5 is to be formed. In 13 Jan 2005, 00:51
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The number of ways you can choose 5 out of 10 members (6M + 4W) is 10C5 = 252

Ways that all the chosen 5 are men only = 6C5 = 6

The number of ways if the committee is to include at least one woman =
252 - 6 = 246

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From 6 men and 4 women a committee of 5 is to be formed. In how many ways this can be done if the committee is to include at least one woman.
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From 6 men and 4 women a committee of 5 is to be formed. In 13 Jan 2005, 19:19
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I got 246 too.

Total # of combination with both men & women: 10C5=252

The question asks for combination with at least 1 woman, and this is equivalent to total possible combination - the combination of zero woman.

Total # of combination with zero woman: 6C5 x 4C4 = 6 x 1 = 6

252-6=246

This sort of question always troubles me... :?



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From 6 men and 4 women a committee of 5 is to be formed. In 22 Feb 2026, 18:45
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